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Reduce, fold or scan (Left/Right)?
...hrough the first argument res of our binary operator minus:
val xs = List(1, 2, 3, 4)
def minus(res: Int, x: Int) = {
println(s"op: $res - $x = ${res - x}")
res - x
}
xs.reduceLeft(minus)
// op: 1 - 2 = -1
// op: -1 - 3 = -4 // de-cumulates value -1 in *first* operator arg `res`
// op: -4 - ...
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edited Dec 16 '19 at 11:30
Demi-Lune
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answered Sep 25 '12 at 7:57
Anton GuryanovAnton Guryanov
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