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What is the correct syntax for 'else if'?
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edited Feb 9 '15 at 10:13
answered Mar 7 '10 at 4:20
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What would cause an algorithm to have O(log n) complexity?
...s.
Processing values one digit at a time
How many digits are in the base-10 number n? Well, if there are k digits in the number, then we'd have that the biggest digit is some multiple of 10k. The largest k-digit number is 999...9, k times, and this is equal to 10k + 1 - 1. Consequently, if we k...
How to find the operating system version using JavaScript?
...'(Windows NT 6.1)',
'Windows 8' => '(Windows NT 6.2)|(WOW64)',
'Windows 10' => '(Windows 10.0)|(Windows NT 10.0)',
'Windows NT 4.0' => '(Windows NT 4.0)|(WinNT4.0)|(WinNT)|(Windows NT)',
'Windows ME' => 'Windows ME',
'Open BSD' => 'OpenBSD',
'Sun OS' => 'SunOS',
'Linux' => '(Lin...
Regular expression to match numbers with or without commas and decimals in text
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10 Answers
10
Active
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One-line list comprehension: if-else variants
...ssion you're returning for each element. Thus you need:
[ x if x%2 else x*100 for x in range(1, 10) ]
The confusion arises from the fact you're using a filter in the first example, but not in the second. In the second example you're only mapping each value to another, using a ternary-operator exp...
Why is a round-trip conversion via a string not safe for a double?
...) {}
};
#define I64(x) x##LL
static const unsigned long long rgval64Power10[] = {
// powers of 10
/*1*/ I64(0xa000000000000000),
/*2*/ I64(0xc800000000000000),
/*3*/ I64(0xfa00000000000000),
/*4*/ I64(0x9c40000000000000),
/*5*/ I64(0xc350000000000000),
/*6*/ I64(0xf4240...
Check if user is using IE
...explanatory.
– Neville Nazerane
Mar 10 '14 at 12:19
61
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JS: Check if date is less than 1 hour ago?
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Define
var ONE_HOUR = 60 * 60 * 1000; /* ms */
then you can do
((new Date) - myDate) < ONE_HOUR
To get one hour from a date, try
new Date(myDate.getTime() + ONE_HOUR)
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Checking for the correct number of arguments
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edited Dec 3 '10 at 1:29
answered Dec 3 '10 at 1:16
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jQuery animate backgroundColor
...: [0, 139, 139],
darkgrey: [169, 169, 169],
darkgreen: [0, 100, 0],
darkkhaki: [189, 183, 107],
darkmagenta: [139, 0, 139],
darkolivegreen: [85, 107, 47],
darkorange: [255, 140, 0],
darkorchid: [153, 50, 204],
darkred: [139, 0, 0],
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