大约有 4,700 项符合查询结果（耗时：0.0116秒） [XML]
How to unzip files programmatically in Android?
...y
//FileExt.kt
data class ZipIO (val entry: ZipEntry, val output: File)
fun File.unzip(unzipLocationRoot: File? = null) {
val rootFolder = unzipLocationRoot ?: File(parentFile.absolutePath + File.separator + nameWithoutExtension)
if (!rootFolder.exists()) {
rootFolder.mkdirs()
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Python: TypeError: cannot concatenate 'str' and 'int' objects [duplicate]
... you want to concatenate int or floats to a string you must use this:
i = 123
a = "foobar"
s = a + str(i)
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Function overloading in Javascript - Best practices
What is the best way(s) to fake function overloading in Javascript?
36 Answers
36
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Django class-based view: How do I pass additional parameters to the as_view method?
...name = 'my_named_view')
then the slug will be available inside your view functions (such as 'get_queryset') like this:
self.kwargs['slug']
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read file from assets
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one line solution for kotlin:
fun readFileText(fileName: String): String {
return assets.open(fileName).bufferedReader().use { it.readText() }
}
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How to correct TypeError: Unicode-objects must be encoded before hashing?
...PY3):
import hashlib, os
password_salt = os.urandom(32).hex()
password = '12345'
hash = hashlib.sha512()
hash.update(('%s%s' % (password_salt, password)).encode('utf-8'))
password_hash = hash.hexdigest()
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Android mock location on device?
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Fun enough, though.
– etienne
Jun 14 '12 at 17:41
23
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Get selected element's outer HTML
...et the HTML of a selected object with jQuery. I am aware of the .html() function; the issue is that I need the HTML including the selected object (a table row in this case, where .html() only returns the cells inside the row).
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How to assert greater than using JUnit Assert?
...Error: timestamp
Expected: a value greater than <456L>
but: <123L> was less than <456L>
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How do I convert a String to an int in Java?
... you look at the Java documentation you'll notice the "catch" is that this function can throw a NumberFormatException, which of course you have to handle:
int foo;
try {
foo = Integer.parseInt(myString);
}
catch (NumberFormatException e)
{
foo = 0;
}
(This treatment defaults a malformed numbe...