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error: request for member '..' in '..' which is of non-class type

I have a class with two constructors, one that takes no arguments and one that takes one argument. 9 Answers ...
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Storyboard doesn't contain a view controller with identifier

... Just for future reference: I'm developing on iOS 6 using Storyboards. I was having the same issue, but I could not find the "Identifier" field in the inspector. Instead, just set the field named "Storyboard ID" to what you would name the Identifier. This field can be found under th...
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How to fire AJAX request Periodically?

This script reloads or refresh the page after every 5 seconds. But I want to do it using jQuery and AJAX call. Is it possible? ...
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How do I view the SQL generated by the Entity Framework?

... select x; var sql = ((System.Data.Objects.ObjectQuery)query).ToTraceString(); or in EF6: var sql = ((System.Data.Entity.Core.Objects.ObjectQuery)query) .ToTraceString(); That will give you the SQL that was generated. ...
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Setting HTTP headers

I'm trying to set a header in my Go web server. I'm using gorilla/mux and net/http packages. 8 Answers ...
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What is the best way to tell if a character is a letter or number in Java without using regexes?

What is the best and/or easiest way to recognize if a string.charAt(index) is an A-z letter or a number in Java without using regular expressions? Thanks. ...
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How to avoid java.util.ConcurrentModificationException when iterating through and removing elements

I have an ArrayList that I want to iterate over. While iterating over it I have to remove elements at the same time. Obviously this throws a java.util.ConcurrentModificationException . ...
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Does adding a duplicate value to a HashSet/HashMap replace the previous value

... Not sure what I'm missing, but the source code seems to indicate otherwise? I see that they don't do a check on the backing HashMap to see if the key already exists before calling put on the backing map? – mystarrocks Jun 9 '14 at 21:36 ...
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Using Java 8 to convert a list of objects into a string obtained from the toString() method

... One simple way is to append your list items in a StringBuilder List<Integer> list = new ArrayList<>(); list.add(1); list.add(2); list.add(3); StringBuilder b = new StringBuilder(); list.forEach(b::append); ...
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About catching ANY exception

...rmat(errno, strerror) except ValueError: print "Could not convert data to an integer." except: print "Unexpected error:", sys.exc_info()[0] raise share | improve this answer | ...