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How to get index using LINQ? [duplicate]
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130
An IEnumerable is not an ordered set.
Although most IEnumerables are ordered, some (such as Dict...
Jenkins Git Plugin: How to build specific tag?
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answered Oct 28 '13 at 10:58
Emmanuel KellerEmmanuel Keller
2,78911 gold badge1111 silver badges1515 bronze badges
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Extract month and year from a zoo::yearmon object
...ere is your example date (properly created!)
date1 <- as.yearmon("Mar 2012", "%b %Y")
Then we can extract the date parts as required:
> format(date1, "%b") ## Month, char, abbreviated
[1] "Mar"
> format(date1, "%Y") ## Year with century
[1] "2012"
> format(date1, "%m") ## numeric mon...
Benefits of inline functions in C++?
...day's optimized compilers, fast CPUs, huge memory etc. (not like in the 1980< where memory was scarce and everything had to fit in 100KB of memory) what advantages do they really have today?
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How to remove extension from string (only real extension!)
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answered Mar 7 '10 at 10:20
nickfnickf
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How to replace all occurrences of a character in string?
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edited Feb 28 '14 at 20:12
answered May 24 '10 at 11:33
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What is the use of ObservableCollection in .net?
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edited Feb 20 '18 at 5:22
Uwe Keim
35.7k3636 gold badges153153 silver badges255255 bronze badges
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Most efficient way to concatenate strings?
...ch better than using the + operator. But I've found that, when executing 1000 concatenations or less, String.Join() is even more efficient than StringBuilder.
StringBuilder sb = new StringBuilder();
sb.Append(someString);
The only problem with String.Join is that you have to concatenate the stri...
Are C# events synchronous?
...// ...
.locals init (class [mscorlib]System.Func`2<int32,string> V_0,
class [mscorlib]System.Func`2<int32,string> V_1,
class [mscorlib]System.Func`2<int32,string> V_2)
IL_0000: ldarg.0
IL_0001: ldfld class [mscorlib]System.Func`2<int32,string&g...
Extract hostname name from string
...= url.split('/')[2];
}
else {
hostname = url.split('/')[0];
}
//find & remove port number
hostname = hostname.split(':')[0];
//find & remove "?"
hostname = hostname.split('?')[0];
return hostname;
}
//test the code
console.log("== Tes...
