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How to generate a random string in Ruby
I'm currently generating an 8-character pseudo-random uppercase string for "A" .. "Z":
50 Answers
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Regex lookahead, lookbehind and atomic groups
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Examples
Given the string foobarbarfoo:
bar(?=bar) finds the 1st bar ("bar" which has "bar" after it)
bar(?!bar) finds the 2nd bar ("bar" which does not have "bar" after it)
(?<=foo)bar finds the 1st bar ("bar" which has "foo" be...
Google Maps Android API v2 Authorization failure
...equired.
Under the Manifest file I replaced the old API KEY value with the
string shortcut created by this new XML file:
android:value="@string/google_maps_key", instead of stating the KEY
directly.
Finally, remove the new MapActivity, but keep the xml file that was
created in that process.
Note: ...
Android image caching
...ge collected during crisis). This could ensue a Reload though.
HashMap<String,SoftReference<Bitmap>> imageCache =
new HashMap<String,SoftReference<Bitmap>>();
writing them on SDcard will not require a Reload; just a user-permission.
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How to parse a query string into a NameValueCollection in .NET
I would like to parse a string such as p1=6&p2=7&p3=8 into a NameValueCollection .
19 Answers
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How to render a DateTime in a specific format in ASP.NET MVC 3?
...ender it in a specific format - for example in the format which ToLongDateString() returns?
15 Answers
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How can I generate an MD5 hash?
Is there any method to generate MD5 hash of a string in Java?
34 Answers
34
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mmap() vs. reading blocks
...into your process. It's as if you memory mapped it yourself except with an extra copy step.
– Chris Smith
Oct 26 '08 at 21:53
6
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What is context in _.each(list, iterator, [context])?
...pluck, 2);
Even from the limited examples, you can see how powerful an "extra argument" can be for creating re-usable code. Instead of making a different callback function for each situation, you can usually adapt a low-level helper. The goal is to have your custom logic bundling a verb and two n...
getting type T from IEnumerable
...yEnumerable.GetType().GetGenericArguments()[0];
Thusly,
IEnumerable<string> strings = new List<string>();
Console.WriteLine(strings.GetType().GetGenericArguments()[0]);
prints System.String.
See MSDN for Type.GetGenericArguments.
Edit: I believe this will address the concerns in ...