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Insert line after first match using sed
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Note the standard sed syntax (as in POSIX, so supported by all conforming sed implementations around (GNU, OS/X, BSD, Solaris...)):
sed '/CLIENTSCRIPT=/a\
CLIENTSCRIPT2="hello"' file
Or on one line:
sed -e '/CLIENTSCRIPT=/a\' -e 'CLIENTSCRIPT2="hello"' file
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Keyword not supported: “data source” initializing Entity Framework Context
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Craig StuntzCraig Stuntz
123k1212 gold badges244244 silver badges266266 bronze badges
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Adding a collaborator to my free GitHub account?
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123
Go to Manage Access page under settings (https://github.com/user/repo/settings/access) and add...
rreplace - How to replace the last occurrence of an expression in a string?
... = s.rsplit(old, occurrence)
... return new.join(li)
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>>> s
'1232425'
>>> rreplace(s, '2', ' ', 2)
'123 4 5'
>>> rreplace(s, '2', ' ', 3)
'1 3 4 5'
>>> rreplace(s, '2', ' ', 4)
'1 3 4 5'
>>> rreplace(s, '2', ' ', 0)
'1232425'
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NSLog the method name with Objective-C in iPhone
...happens to be implemented as a C-string (as of the current versions of Mac OS X and the iPhone OS) doesn't mean you should use it in that way, since Apple could change it in an OS update.
– Nick Forge
May 5 '10 at 8:06
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How to set the matplotlib figure default size in ipython notebook?
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123
I believe the following work in version 0.11 and above. To check the version:
$ ipython --ver...
Slow Requests on Local Flask Server
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Ok I figured it out. It appears to be an issue with Werkzeug and os's that support ipv6.
From the Werkzeug site http://werkzeug.pocoo.org/docs/serving/:
On operating systems that support ipv6 and have it configured such as modern Linux systems, OS X 10.4 or higher as well as Windows V...
Is there a Python Library that contains a list of all the ascii characters?
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If you want all printable characters:
>>> string.printable
'0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;?@[\\]^_`{|}~ \t\n\r\x0b\x0c'
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指定组件的大小 · App Inventor 2 中文网
... 隐私策略和使用条款 技术支持 service@fun123.cn
How can I format a number into a string with leading zeros?
... i.ToString("0000000000");
Replace with as many digits as you like.
i = 123 will then result in Key = "0000000123".
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