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Best practices/guidance for maintaining assembly version numbers
...context we use TeamCity and Subversion/Git. TeamCity is free for a small (10) number of projects and is a very good build server but there are others, some of which are completely free.
What a version number means
What a version means to one person may mean something different to another, the gene...
Drop shadow for PNG image in CSS
...s for IE.
.shadowed {
-webkit-filter: drop-shadow(12px 12px 25px rgba(0,0,0,0.5));
filter: url(#drop-shadow);
-ms-filter: "progid:DXImageTransform.Microsoft.Dropshadow(OffX=12, OffY=12, Color='#444')";
filter: "progid:DXImageTransform.Microsoft.Dropshadow(OffX=12, OffY=12, Color='#4...
Iterate a list with indexes in Python
...e this [3, 7, 19] and makes it into iterable list of tuples, like so: [(0,3), (1,7), (2,19)] to use it instead of:
6 An...
XMLHttpRequest status 0 (responseText is empty)
Cannot get data with XMLHttpRequest (status 0 and responseText is empty):
19 Answers
1...
Rails 3: I want to list all paths defined in my rails application
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230
rake routes
or
bundle exec rake routes
...
Is it possible to specify your own distance function using scikit-learn K-Means Clustering?
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80
Here's a small kmeans that uses any of the 20-odd distances in
scipy.spatial.distance, or a user...
Retrieve list of tasks in a queue in Celery
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180
EDIT: See other answers for getting a list of tasks in the queue.
You should look here:
Celery ...
Python: Tuples/dictionaries as keys, select, sort
...ies of fruits of different colors, e.g., 24 blue bananas, 12 green apples, 0 blue strawberries and so on.
I'd like to organize them in a data structure in Python that allows for easy selection and sorting. My idea was to put them into a dictionary with tuples as keys, e.g.,
...
How to get first element in a list of tuples?
...
>>> a = [(1, u'abc'), (2, u'def')]
>>> [i[0] for i in a]
[1, 2]
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Check if all elements in a list are identical
..., for Python 2.7 and (only s1, s4, s7, s9 should return True)
s1 = [1] * 5000
s2 = [1] * 4999 + [2]
s3 = [2] + [1]*4999
s4 = [set([9])] * 5000
s5 = [set([9])] * 4999 + [set([10])]
s6 = [set([10])] + [set([9])] * 4999
s7 = [1,1]
s8 = [1,2]
s9 = []
we get
| checkEqual1 | checkEqual2 | checkE...