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POST JSON to API using Rails and HTTParty

... I solved this by adding .to_json and some heading information @result = HTTParty.post(@urlstring_to_post.to_str, :body => { :subject => 'This is the screen name', :issue_type => 'Application Problem', :stat...
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How to create correct JSONArray in Java using JSONObject

how can I create a JSON Object like the following, in Java using JSONObject ? 4 Answers ...
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How to get visitor's location (i.e. country) using geolocation? [duplicate]

...function(response) { console.log(response.city, response.country); }, "jsonp"); Here's a more detailed JSFiddle example that also prints out the full response information, so you can see all of the available details: http://jsfiddle.net/zK5FN/2/ The location will generally be less accurate th...
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How to change a field name in JSON using Jackson

I'm using jackson to convert an object of mine to json. The object has 2 fields: 4 Answers ...
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How do I decode a string with escaped unicode?

...ent. For broader compatibility, use the below instead: decodeURIComponent(JSON.parse('"http\\u00253A\\u00252F\\u00252Fexample.com"')); > 'http://example.com' Original answer: unescape(JSON.parse('"http\\u00253A\\u00252F\\u00252Fexample.com"')); > 'http://example.com' You can offload all...
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MFC CListCtrl使用方法详解 - C/C++ - 清泛网 - 专注C/C++及内核技术

...=/library/en-us/wceshellui5/html/wce50lrflistviewstyles.asp 3. 插入数据 m_list.InsertColumn( 0, "ID", LVCFMT_LEFT, 40 ); //插入列 m_list.InsertColumn( 1, "NAME", LVCFMT_LEFT, 50 ); int nRow = m_list.InsertItem(0, "11"); //插入行 m_list.SetItemText(nRow, ...
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SVG图像加载扩展 - 第三方扩展集合 · App Inventor 2 中文网

... 常见应用场景 1. 图标系统 2. 数据可视化 3. 游戏和动画 4. 自定义UI组件 故障排除 常见问题 兼容性说明 开发资源 SVG设计...
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Converting an object to a string

... I would recommend using JSON.stringify, which converts the set of the variables in the object to a JSON string. Most modern browsers support this method natively, but for those that don't, you can include a JS version: var obj = { name: 'myObj' ...
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npm can't find package.json

... I think, npm init will create your missing package.json file. It works for me for the same case. share | improve this answer | follow |...
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Getting the location from an IP address [duplicate]

...: 650 } Here's a PHP example: $ip = $_SERVER['REMOTE_ADDR']; $details = json_decode(file_get_contents("http://ipinfo.io/{$ip}/json")); echo $details->city; // -> "Mountain View" You can also use it client-side. Here's a simple jQuery example: $.get("https://ipinfo.io/json", function ...