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PostgreSQL LIKE query performance variations

...to a particular table in my database. Sometimes I will get results within 200-400 ms (very acceptable) but other times it might take as much as 30 seconds to return results. ...
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\d is less efficient than [0-9]

I made a comment yesterday on an answer where someone had used [0123456789] in a regular expression rather than [0-9] or \d . I said it was probably more efficient to use a range or digit specifier than a character set. ...
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How do I find if a string starts with another string in Ruby?

... answered Nov 12 '10 at 20:02 steenslagsteenslag 71.2k1414 gold badges126126 silver badges157157 bronze badges ...
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Why would finding a type's initializer throw a NullReferenceException?

... with csc test.cs: (196c.1874): Access violation - code c0000005 (first chance) mscorlib_ni!System.RuntimeType.GetConstructorImpl(System.Reflection.BindingFlags, System.Reflection.Binder, System.Reflection.CallingConventions, System.Type[], System.Reflection.ParameterModifier[])+0x...
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Decimal separator comma (',') with numberDecimal inputType in EditText

... 105 A workaround (until Google fix this bug) is to use an EditText with android:inputType="numberDe...
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Where is the WPF Numeric UpDown control?

... 50 Simply use the IntegerUpDown control in the xtended wpf toolkit You can use it like this: Add ...
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How can I test that a value is “greater than or equal to” in Jasmine?

I want to confirm that a value is a decimal (or 0), so the number should be greater than or equal to zero and less than 1. ...
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An example of how to use getopts in bash

... #!/bin/bash usage() { echo "Usage: $0 [-s <45|90>] [-p <string>]" 1>&2; exit 1; } while getopts ":s:p:" o; do case "${o}" in s) s=${OPTARG} ((s == 45 || s == 90)) || usage ;; p) ...
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Is there any way to prevent input type=“number” getting negative values?

... Use the min attribute like this: <input type="number" min="0"> share | improve this answer | follow | ...
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What's the best way to check if a String represents an integer in Java?

...ncerned with potential overflow problems this function will perform about 20-30 times faster than using Integer.parseInt(). public static boolean isInteger(String str) { if (str == null) { return false; } int length = str.length(); if (length == 0) { return false; ...