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How to get numbers after decimal point?
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NOTE: This solution returns a string including the dot (.55), which you may not expect due the questions title!
– T. Christiansen
Mar 13 '15 at 8:18
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Removing the first 3 characters from a string [closed]
What is the most efficient way to remove the first 3 characters of a string?
3 Answers
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SQL command to display history of queries
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well not all, suppression occurs for some that contain strings like "password".
– mckenzm
May 15 '15 at 18:44
1
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Redirect to Action in another controller
...irectToAction broke and I got it to work using the area = "" with an empty string.
– Jonathan Alfaro
Sep 28 '16 at 16:47
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Use jQuery to get the file input's selected filename without the path
...he path to a file on your computer.
To get just the filename portion of a string, you can use split()...
var file = path.split('\\').pop();
jsFiddle.
...or a regular expression...
var file = path.match(/\\([^\\]+)$/)[1];
jsFiddle.
...or lastIndexOf()...
var file = path.substr(path.lastInde...
Sublime text 2 - find and replace globally ( all files and in all directories )
Is there any way to find and replace text string automatically in all folder's files ?
2 Answers
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How can I use a carriage return in a HTML tooltip?
... three codes don't seem to be HTML. They look more like C-derived language string escape sequences.
– Sam
Jan 7 '15 at 1:31
3
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ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'db'
... but they didnt have privileges, or even with any non existing thinked out string user 'sdasdsa', but the current user was always anonymous, after dropping him it started to work
– FantomX1
yesterday
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Bash script to calculate time elapsed
...t of an arithmetic operation. You're using $() which is simply taking the string and evaluating it as a command. It's a bit of a subtle distinction. Hope this helps.
As tink pointed out in the comments on this answer, $[] is deprecated, and $(()) should be favored.
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Understanding Spliterator, Collector and Stream in Java 8
...ectors include:
summing, e.g. Collectors.reducing(0, (x, y) -> x + y)
StringBuilder appending, e.g. Collector.of(StringBuilder::new, StringBuilder::append, StringBuilder::append, StringBuilder::toString)
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