大约有 40,900 项符合查询结果(耗时:0.0285秒) [XML]
Mean per group in a data.frame [duplicate]
....table(text=
'Name Month Rate1 Rate2
Aira 1 12 23
Aira 2 18 73
Aira 3 19 45
Ben 1 53 19
Ben 2 22 87
Ben 3 19 45
Cat 1 22 87
Cat 2 67 43
Cat ...
How can I delete one element from an array by value
...
I think I've figured it out:
a = [3, 2, 4, 6, 3, 8]
a.delete(3)
#=> 3
a
#=> [2, 4, 6, 8]
share
|
improve this answer
|
follow
...
How can I sort a dictionary by key?
What would be a nice way to go from {2:3, 1:89, 4:5, 3:0} to {1:89, 2:3, 3:0, 4:5} ?
I checked some posts but they all use the "sorted" operator that returns tuples.
...
For each row return the column name of the largest value
...amples using sample reproducible):
DF <- data.frame(V1=c(2,8,1),V2=c(7,3,5),V3=c(9,6,4))
colnames(DF)[apply(DF,1,which.max)]
[1] "V3" "V1" "V2"
A faster solution than using apply might be max.col:
colnames(DF)[max.col(DF,ties.method="first")]
#[1] "V3" "V1" "V2"
...where ties.method can be...
Applying a function to every row of a table using dplyr?
... |
edited Aug 6 '19 at 3:20
answered Jul 14 '14 at 0:20
...
How do you match only valid roman numerals with a regular expression?
...
330
You can use the following regex for this:
^M{0,4}(CM|CD|D?C{0,3})(XC|XL|L?X{0,3})(IX|IV|V?I{0...
Does assignment with a comma work?
Why does aaa = 1,2,3 work and set the value of aaa to 1 ?
4 Answers
4
...
“ValueError: zero length field name in format” error in Python 3.0,3.1,3.2
I'm trying learn Python (3 to be more specific) and I'm getting this error:
3 Answers
...
Version of SQLite used in Android?
...database.sqlite package-level javadoc
Using the emulators:
adb shell sqlite3 --version
UPDATE: Since SDK 29 (emulator revision 8), the adb shell command gives:
/system/bin/sh: sqlite3: inaccessible or not found
Any ideas why? Issue tracker here.
SQLite 3.28.0 (window functions!):
30-11.0-R (Re...
Reshape three column data frame to matrix (“long” to “wide” format) [duplicate]
...similar questions scattered around this site.
tmp <- data.frame(x=gl(2,3, labels=letters[24:25]),
y=gl(3,1,6, labels=letters[1:3]),
z=c(1,2,3,3,3,2))
Using the tidyverse:
The new cool new way to do this is with pivot_wider from tidyr 1.0.0. It returns a d...