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Interview question: Check if one string is a rotation of other string [closed]
...ink there are.)
– Jon Skeet
Mar 31 '10 at 14:55
6
You can also use (s1+s1).contains(s2) in Java.
...
Finding all possible combinations of numbers to reach a given sum
..., partial + [n])
if __name__ == "__main__":
subset_sum([3,9,8,4,5,7,10],15)
#Outputs:
#sum([3, 8, 4])=15
#sum([3, 5, 7])=15
#sum([8, 7])=15
#sum([5, 10])=15
This type of algorithms are very well explained in the following Standford's Abstract Programming lecture - this ...
Way to get number of digits in an int?
... may be flawed too i am no benchmark expert). Over a large number of runs (100 000 000), the speed is 11s to 8s on my machine hardly twice as fast.
– Jean
Aug 20 '09 at 15:36
5
...
How to compare two strings in dot separated version format in Bash?
...ty fields in ver2 with zeros
ver2[i]=0
fi
if ((10#${ver1[i]} > 10#${ver2[i]}))
then
return 1
fi
if ((10#${ver1[i]} < 10#${ver2[i]}))
then
return 2
fi
done
return 0
}
testvercomp () {
vercom...
How to round float numbers in javascript?
...
var number = 6.688689;
var roundedNumber = Math.round(number * 10) / 10;
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Efficient way to determine number of digits in an integer
...
107
Well, the most efficient way, presuming you know the size of the integer, would be a lookup. ...
C++ performance challenge: integer to std::string conversion
...
#include <string>
const char digit_pairs[201] = {
"00010203040506070809"
"10111213141516171819"
"20212223242526272829"
"30313233343536373839"
"40414243444546474849"
"50515253545556575859"
"60616263646566676869"
"70717273747576777879"
"80818283848586878889"
"909...
How to compare software version number using js? (only number)
.../Xv9WL/28
– ripper234
Mar 13 '12 at 10:36
5
Hey All, I've rolled this gist into a gitrepo with te...
Putting a simple if-then-else statement on one line [duplicate]
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edited May 23 '17 at 12:10
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111 silver badge
answered May 10 '10 at 13:00
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finding and replacing elements in a list
...1]
>>> for n, i in enumerate(a):
... if i == 1:
... a[n] = 10
...
>>> a
[10, 2, 3, 4, 5, 10, 2, 3, 4, 5, 10]
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