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How to do multiple arguments to map function where one remains the same in python?

... 192 One option is a list comprehension: [add(x, 2) for x in [1, 2, 3]] More options: a = [1, 2, ...
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Reshape three column data frame to matrix (“long” to “wide” format) [duplicate]

...o similar questions scattered around this site. tmp <- data.frame(x=gl(2,3, labels=letters[24:25]), y=gl(3,1,6, labels=letters[1:3]), z=c(1,2,3,3,3,2)) Using the tidyverse: The new cool new way to do this is with pivot_wider from tidyr 1.0.0. It returns a...
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Looping in a spiral

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App Inventor 2 列表代码块 · App Inventor 2 中文网

...生成 App 鸿蒙 · 一套积木,多端原生打包! 下载 AI2伴侣 · 安卓/鸿蒙/iOS aia 源码商店 中文社区 中文教育版 各版本对比 关于 关于我们 发布日志 服务条款 ...
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In Matplotlib, what does the argument mean in fig.add_subplot(111)?

... a single integer. For example, "111" means "1x1 grid, first subplot" and "234" means "2x3 grid, 4th subplot". Alternative form for add_subplot(111) is add_subplot(1, 1, 1). share | improve this an...
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How do I find the duplicates in a list and create another list with them?

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How can building a heap be O(n) time complexity?

...ap. The work required for the siftDown approach is given by the sum (0 * n/2) + (1 * n/4) + (2 * n/8) + ... + (h * 1). Each term in the sum has the maximum distance a node at the given height will have to move (zero for the bottom layer, h for the root) multiplied by the number of nodes at that hei...
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AI 一句话生成 App:ai2-app 技能,直接编译安卓鸿蒙 - App Inventor 2 中文网

... WorkBuddy 等) 网页版 AI 导入或更新 ai2-app 技能包(下载 https://www.fun123.cn/static/ai2-app/ai2-app.zip 并解压到你的技能目录),然后用这个技能完成我的需求,交付可直接导入 App Inventor 2 中文网(fun123.cn)编译的 .a...
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【科普】App Inventor 2 中的"2"是什么意思? · App Inventor 2 中文网

...生成 App 鸿蒙 · 一套积木,多端原生打包! 下载 AI2伴侣 · 安卓/鸿蒙/iOS aia 源码商店 中文社区 中文教育版 各版本对比 关于 关于我们 发布日志 服务条款 ...
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Split delimited strings in a column and insert as new rows [duplicate]

...is another way of doing it.. df <- read.table(textConnection("1|a,b,c\n2|a,c\n3|b,d\n4|e,f"), header = F, sep = "|", stringsAsFactors = F) df ## V1 V2 ## 1 1 a,b,c ## 2 2 a,c ## 3 3 b,d ## 4 4 e,f s <- strsplit(df$V2, split = ",") data.frame(V1 = rep(df$V1, sapply(s, length))...