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Do a “git export” (like “svn export”)?
...st way to achieve this is with git archive. If you really need just the expanded tree you can do something like this.
git archive master | tar -x -C /somewhere/else
Most of the time that I need to 'export' something from git, I want a compressed archive in any case so I do something like this.
g...
What do the &,
... out explicitly, in the file below it uses some characters I do not understand. What does each line and symbol(&,*,
5 Answe...
jQuery post() with serialize and extra data
I'm trying to find out if it's possible to post serialize() and other data that's outside the form.
9 Answers
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Breaking up long strings on multiple lines in Ruby without stripping newlines
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I'm fairly sure that it's not; I tried both undef'ing and redefining String#+ and it doesn't seem like anything is being sent there.
– Jessehz
May 9 '12 at 22:08
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what does the __file__ variable mean/do?
...But there is a reason for these statements that determine path at runtime, and I would really like to understand the os.path module so that I can start using it.
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Getting list of parameter names inside python function [duplicate]
Is there an easy way to be inside a python function and get a list of the parameter names?
4 Answers
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How do I enable standard copy paste for a TextView in Android?
I want to enable standard copy paste for a TextView (the same as for EditText). How can I do it?
9 Answers
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How do I get the find command to print out the file size with the file name?
If I issue the find command as follows:
15 Answers
15
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Using JSON.NET as the default JSON serializer in ASP.NET MVC 3 - is it possible?
...sponse.ContentEncoding = ContentEncoding;
// If you need special handling, you can call another form of SerializeObject below
var serializedObject = JsonConvert.SerializeObject(Data, Formatting.Indented);
response.Write(serializedObject);
}
EDIT 2: I removed the check ...
How to change options of with jQuery?
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You can remove the existing options by using the empty method, and then add your new options:
var option = $('<option></option>').attr("value", "option value").text("Text");
$("#selectId").empty().append(option);
If you have your new options in an object you can:
var newO...