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Convert objective-c typedef to its string equivalent
...tType {
NSString *result = nil;
switch(formatType) {
case JSON:
result = @"JSON";
break;
case XML:
result = @"XML";
break;
case Atom:
result = @"Atom";
break;
case RSS:
result...
Tool for generating railroad diagram used on json.org [closed]
I love the syntax of railroad diagrams on json.org which are a graphical representation of the BNF language. I haven't found any tools that can produce results as eloquently.
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failed to serialize the response in Web API
...ed answer did not work for me because it only changes the behaviour of the JSON formatter, but I was getting XML when I called the service from the browser.
To fix this, I switched off XML and forced only JSON to be returned.
In the Global.asax file, put the following lines at the top of your App...
How to escape a JSON string to have it in a URL?
.... The parameters to the page are in a Javascript array that I serialize in JSON.
6 Answers
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POST JSON to API using Rails and HTTParty
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I solved this by adding .to_json and some heading information
@result = HTTParty.post(@urlstring_to_post.to_str,
:body => { :subject => 'This is the screen name',
:issue_type => 'Application Problem',
:stat...
Remove a JSON attribute [duplicate]
if I have a JSON object say:
2 Answers
2
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How to create correct JSONArray in Java using JSONObject
how can I create a JSON Object like the following, in Java using JSONObject ?
4 Answers
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How to get visitor's location (i.e. country) using geolocation? [duplicate]
...function(response) {
console.log(response.city, response.country);
}, "jsonp");
Here's a more detailed JSFiddle example that also prints out the full response information, so you can see all of the available details: http://jsfiddle.net/zK5FN/2/
The location will generally be less accurate th...
How to change a field name in JSON using Jackson
I'm using jackson to convert an object of mine to json.
The object has 2 fields:
4 Answers
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How do I decode a string with escaped unicode?
...ent. For broader compatibility, use the below instead:
decodeURIComponent(JSON.parse('"http\\u00253A\\u00252F\\u00252Fexample.com"'));
> 'http://example.com'
Original answer:
unescape(JSON.parse('"http\\u00253A\\u00252F\\u00252Fexample.com"'));
> 'http://example.com'
You can offload all...