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Why does this code using random strings print “hello world”?
....Random is constructed with a specific seed parameter (in this case -229985452 or -147909649), it follows the random number generation algorithm beginning with that seed value.
Every Random constructed with the same seed will generate the same pattern of numbers every time.
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Can You Get A Users Local LAN IP Address Via JavaScript?
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answered Nov 10 '14 at 18:49
afourneyafourney
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Difference between binary tree and binary search tree
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Eneko Alonso
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answered Jun 17 '11 at 0:55
user541686user541686
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How to execute mongo commands through shell scripts?
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466
You can also evaluate a command using the --eval flag, if it is just a single command.
mongo ...
How can I convert a string to a number in Perl?
...g into a floating point variable. So an example of the string I have is "5.45" and I want a floating point equivalent so I can add .1 to it. I have searched around the internet, but I only see how to convert a string to an integer.
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How does UTF-8 “variable-width encoding” work?
The unicode standard has enough code-points in it that you need 4 bytes to store them all. That's what the UTF-32 encoding does. Yet the UTF-8 encoding somehow squeezes these into much smaller spaces by using something called "variable-width encoding".
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How to pass an object from one activity to another on Android
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Master
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answered Apr 29 '10 at 10:39
SamuhSamuh
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Why does a base64 encoded string have an = sign at the end
I know what base64 encoding is and how to calculate base64 encoding in C#, however I have seen several times that when I convert a string into base64, there is an = at the end.
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Http Basic Authentication in Java using HttpClient?
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Have you tried this (using HttpClient version 4):
String encoding = Base64Encoder.encode(user + ":" + pwd);
HttpPost httpPost = new HttpPost("http://host:post/test/login");
httpPost.setHeader(HttpHeaders.AUTHORIZATION, "Basic " + encoding);
System.out.println("executin...
PHP convert date format dd/mm/yyyy => yyyy-mm-dd [duplicate]
...is assumed. Check more here.
Use the default date function.
$var = "20/04/2012";
echo date("Y-m-d", strtotime($var) );
EDIT I just tested it, and somehow, PHP doesn't work well with dd/mm/yyyy format. Here's another solution.
$var = '20/04/2012';
$date = str_replace('/', '-', $var);
echo date(...