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std::string to float or double
... "0.6";
double temp = ::atof(num.c_str());
Does it for me, it is a valid C++ syntax to convert a string to a double.
You can do it with the stringstream or boost::lexical_cast but those come with a performance penalty.
Ahaha you have a Qt project ...
QString winOpacity("0.6");
double temp = w...
Resolving ambiguous overload on function pointer and std::function for a lambda using +
...e is observable by a program, then it's illegal. Once I asked in comp.lang.c++.moderated if a closure type could add a typedef for result_type and the other typedefs required to make them adaptable (for instance by std::not1). I was told that it could not because this was observable. I'll try to fin...
For every character in string
How would I do a for loop on every character in string in C++?
9 Answers
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make_unique and perfect forwarding
Why is there no std::make_unique function template in the standard C++11 library? I find
6 Answers
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How do I make a fully statically linked .exe with Visual Studio Express 2005?
My current preferred C++ environment is the free and largely excellent Microsoft Visual Studio 2005 Express edition. From time to time I have sent release .exe files to other people with pleasing results. However recently I made the disturbing discovery that the pleasing results were based on more l...
Logic to test that 3 of 4 are True
... seems natural to me that the value 3 appears somewhere.
For instance, in C++:
if ((int)a + (int)b + (int)c + (int)d == 3)
...
This is well defined in C++: the standard (§4.7/4) indicates that converting bool to int gives the expected values 0 or 1.
In Java and C#, you can use the followin...
Pretty-print C++ STL containers
...streams.
Finally, I've used std::enable_if, which is available as part of C++0x, and works in Visual C++ 2010 and g++ 4.3 (needs the -std=c++0x flag) and later. This way there is no dependency on Boost.
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do {…} while(false)
...o out of a block most definitely causes local variables to be destroyed in C++, same as break. And in C variables aren't really destroyed, their stack space is simply reclaimed.
– Ben Voigt
Feb 23 '10 at 16:00
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C libcurl get output into a string
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for C++ std::string go here
– Trevor Boyd Smith
Sep 4 '18 at 14:40
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Overloading member access operators ->, .*
...ry dereferencing operator * (i.e. the first part of what -> does).
The C++ -> operator is basically the union of two steps and this is clear if you think that x->y is equivalent to (*x).y. C++ allows you to customize what to do with the (*x) part when x is an instance of your class.
The s...