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How to [recursively] Zip a directory in PHP?
...ce), file_get_contents($source));
}
return $zip->close();
}
Call it like this:
Zip('/folder/to/compress/', './compressed.zip');
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how to check the jdk version used to compile a .class file [duplicate]
...the ".class" in the command otherwise I got a message, "Error: Cannot find foo.class". So doing, "javap -verbose foo | grep "major"" worked. Just a heads up. stackoverflow.com/questions/13356811/…
– Kyle Bridenstine
Dec 1 '15 at 19:21
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Ruby - test for array
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Type checking is for Java. Go ahead and just call count on the variable. Write unit tests to make sure the method works as expected.
– user132447
Mar 21 '12 at 14:55
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设置用户默认权限 Umask命令详解 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...22 = 644
注：权限计算实际上是二进制位的与操作，参考All About the umask and Permissions。
操作bar.tar
shell> tar xf bar.tar
这次有点不同，我们要运行两次tar命令。
第一次：以root身份运行tar命令，然后查看目录和文件的权限，分别...
What is the difference between UNION and UNION ALL?
What is the difference between UNION and UNION ALL ?
26 Answers
26
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Command not found error in Bash variable assignment
I have this script called test.sh:
5 Answers
5
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What do (lambda) function closures capture?
...the name and scope of the variable, not the object it's pointing to. Since all the functions in your example are created in the same scope and use the same variable name, they always refer to the same variable.
EDIT: Regarding your other question of how to overcome this, there are two ways that com...
Command not found when using sudo
I have a script called foo.sh in my home folder.
9 Answers
9
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Git copy file preserving history [duplicate]
...ile has been deleted and another one created, while "git diff -M" will actually detect the move and display the change accordingly (see "man git diff" for details).
So in git this is not a matter of how you commit your changes but how you look at the committed changes later.
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Reverse of JSON.stringify?
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JSON.stringify and JSON.parse are almost oposites, and "usually" this kind of thing will work:
var obj = ...;
var json = JSON.stringify(obj);
var obj2 = JSON.parse(json);
so that obj and obj2 are "the same".
However there are some limitations to be aware of.
Often these issues ...