大约有 19,000 项符合查询结果（耗时：0.0327秒） [XML]
GROUP_CONCAT comma separator - MySQL
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How do I find which rpm package supplies a file I'm looking for?
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Furthermore, yum whatprovides ... only requires root if the application is a root package (i.e. it resides in /sbin). However, rpm -qf ... also requires root in order to read rpms from /sbin. Therefore, I propose that the root requirements are functionally equivalent for b...
MySQL how to join tables on two fields
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No Swipe Back when hiding Navigation Bar in UINavigationController
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In my case, to prevent strange effects
Root view controller
override func viewDidLoad() {
super.viewDidLoad()
// Enable swipe back when no navigation bar
navigationController?.interactivePopGestureRecognizer?.delegate = self
}
func gestureRecogni...
When to use MongoDB or other document oriented database systems? [closed]
...orm for video- and audio-clips, photos and vector-grafics. We started with MySQL as the database backend and recently included MongoDB for storing all meta-information of the files, because MongoDB better fits the requirements. For example: photos may have Exif information, videos may have audio...
MySQL Query to select data from last week?
Hi I have a table with a date field and some other information.
I want to select all entries from the past week, (week start from Sunday).
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Which is more efficient: Multiple MySQL tables or one large table?
I store various user details in my MySQL database. Originally it was set up in various tables meaning data is linked with UserIds and outputting via sometimes complicated calls to display and manipulate the data as required. Setting up a new system, it almost makes sense to combine all of these tabl...
What are file descriptors, explained in simple terms?
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COMMAND PID USER FD TYPE DEVICE SIZE/OFF NODE NAME
sleep 14726 root cwd DIR 8,1 4096 1201140 /home/x
sleep 14726 root rtd DIR 8,1 4096 2 /
sleep 14726 root txt REG 8,1 35000 786587 /bin/sleep
sleep 14726 root mem REG 8,1 11864720 118650...
MySQL COUNT DISTINCT
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Why is SSE scalar sqrt(x) slower than rsqrt(x) * x?
...th on an Intel Core Duo, and while looking at various approaches to square root I've noticed something odd: using the SSE scalar operations, it is faster to take a reciprocal square root and multiply it to get the sqrt, than it is to use the native sqrt opcode!
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