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Strip spaces/tabs/newlines - python

...r.split([sep[, maxsplit]]) with no sep or sep=None: From docs: If sep is not specified or is None, a different splitting algorithm is applied: runs of consecutive whitespace are regarded as a single separator, and the result will contain no empty strings at the start or end if the string ...
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How do I convert array of Objects into one Object in JavaScript?

... You're probably looking for something like this: // original var arr = [ {key : '11', value : '1100', $$hashKey : '00X' }, {key : '22', value : '2200', $$hashKey : '018' } ]; //convert var result = {}; for (var i = 0; i < arr.length; i++) { resu...
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Exact time measurement for performance testing [duplicate]

What is the most exact way of seeing how long something, for example a method call, took in code? 7 Answers ...
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Clearing purchases from iOS in-app purchase sandbox for a test user

... share | improve this answer | follow | edited Apr 13 '17 at 12:57 Community♦ 111 silver...
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How can I convert bigint (UNIX timestamp) to datetime in SQL Server?

... share | improve this answer | follow | edited Mar 4 '15 at 23:19 Diego 16.4k55 gold badge...
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How to convert QString to std::string?

I am trying to do something like this: 10 Answers 10 ...
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PHP 5.4 Call-time pass-by-reference - Easy fix available?

Is there any way to easily fix this issue or do I really need to rewrite all the legacy code? 3 Answers ...
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jQuery set checkbox checked

... share | improve this answer | follow | edited May 23 '17 at 11:47 Community♦ 111 silver...
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How do I perform the SQL Join equivalent in MongoDB?

... As of Mongo 3.2 the answers to this question are mostly no longer correct. The new $lookup operator added to the aggregation pipeline is essentially identical to a left outer join: https://docs.mongodb.org/master/reference/operator/aggregation/lookup/#pipe....
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convert '1' to '0001' in JavaScript [duplicate]

... '0001' in JavaScript without using any 3rd party libraries. I have done this in php using spritf: $time = sprintf('%04.0f',$time_arr[$i]); ...