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VC MFC工具栏(CToolBar)控件 - C/C++ - 清泛网 - 专注C/C++及内核技术

...态标志 BYTE fsStyle; //按钮风格 DWORD dwData; // 用户定义的数据 int iString; // 按钮显示的文本内容索引,无为NULL。 } TBBUTTON; “MFC类库详解”关于fsState和fsStyle参数的解释如下: fsState 按钮的状态标志。它可以是下面列出的值的...
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移动前端开发之viewport的深入理解 - 更多技术 - 清泛网 - 专注C/C++及内核技术

...,第三篇),有兴趣的同学可以去看一下,本文中有很多数据和观点也是出自那里。ppk认为,移动设备上有三个viewport。 首先,移动设备上的浏览器认为自己必须能让所有的网站都正常显示,即使是那些不是为移动设备设计...
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cpuid汇编指令 - C/C++ - 清泛网 - 专注C/C++及内核技术

...可以确定CPU的具体型号,以下是部分Intel CPU的处理器签名数据(资料来自Intel): 前面说过,80386尽管没有CPUID指令,但在复位时也是可以返回处理器签名的,下面是80386返回的处理器签名的格式: 下面是80386处理...
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深入理解 x86/x64 的中断体系 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术

...了权限控制机制,为了支持权限的控制增添了几个重要的数据结构,下面是与中断相关的结构: gate descriptor(门描述符):用于描述和控制 Interrupt Service Routine 的访问,中断可使用的 gate 包括: Interrupt-gate descriptor(中断门...
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google mock分享(全网最全最好的gmock文档,没有之一) - C/C++ - 清泛网 ...

...个Query,将Query的Segment(如q=mp3、retail_wholesale=0放到一个数据结构中) 引擎会调用另外内部模块具体根据这些Segment来处理相应的业务逻辑。 由于Google Mock不能Mock模版方法,因此我稍微更改了一下原本的接口,以便演示: 我...
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Dokan虚拟磁盘开发实战 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术

...不细说了。 Dokan客户端则由Delphi开发,其参考代码来自网络上的Delphi例子,比如Mirror Driver。 本篇文章主要是Dokan开发过程的一些总结,所以不会对Dokan本身做介绍,与Dokan有关的资料及代码,请到google里搜索,或到Dokan的官方网...
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NSRange to Range

... juancazalla 9461010 silver badges1616 bronze badges answered Oct 22 '14 at 21:46 Alex PretzlavAlex Pretzlav 15....
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u'\ufeff' in Python string

...BOM, and is used to tell the difference between big- and little-endian UTF-16 encoding. If you decode the web page using the right codec, Python will remove it for you. Examples: #!python2 #coding: utf8 u = u'ABC' e8 = u.encode('utf-8') # encode without BOM e8s = u.encode('utf-8-sig') # ...
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How many bytes does one Unicode character take?

...s information. Those are the various unicode encodings, such as utf-8, utf-16le, utf-32 etc. They are distinguished largely by the size of of their codeunits. UTF-32 is the simplest encoding, it has a codeunit that is 32bits, which means an individual codepoint fits comfortably into a codeunit. The ...
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What do numbers using 0x notation mean?

... Literals that start with 0x are hexadecimal integers. (base 16) The number 0x6400 is 25600. 6 * 16^3 + 4 * 16^2 = 25600 For an example including letters (also used in hexadecimal notation where A = 10, B = 11 ... F = 15) The number 0x6BF0 is 27632. 6 * 16^3 + 11 * 16^2 + 15 * 16...