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Maven Install on Mac OS X

... OS X prior to Mavericks (10.9) actually comes with Maven 3 built in. If you're on OS X Lion, you won't have java installed by default. Just run java by itself and it'll prompt you to install it. Assuming qualifications are met, run mvn -version and see some output like this: ...
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Multiple linear regression in Python

... my dependent variable (y) against several independent variables (x1, x2, x3, etc.). 13 Answers ...
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pandas DataFrame: replace nan values with average of columns

... 283 You can simply use DataFrame.fillna to fill the nan's directly: In [27]: df Out[27]: ...
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What exactly does += do in python?

...r return self.num >>> a = Adder(2) >>> a += 3 in __iadd__ 3 >>> a 5 Hope this helps. share | improve this answer | follow ...
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Efficient way to rotate a list in python

...method. from collections import deque items = deque([1, 2]) items.append(3) # deque == [1, 2, 3] items.rotate(1) # The deque is now: [3, 1, 2] items.rotate(-1) # Returns deque to original state: [1, 2, 3] item = items.popleft() # deque == [2, 3] ...
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No module named MySQLdb

... 653 You need to use one of the following commands. Which one depends on what OS and software you hav...
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What is the best way to convert an array to a hash in Ruby

...y keys or values! Building on @John Topley's popular answer, let's try: a3 = [ ['apple', 1], ['banana', 2], [['orange','seedless'], 3] ] h3 = Hash[*a3.flatten] This throws an error: ArgumentError: odd number of arguments for Hash from (irb):10:in `[]' from (irb):10 The constru...
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Why am I getting a “401 Unauthorized” error in Maven?

... JohnJohn 6,54199 gold badges3535 silver badges9191 bronze badges 2 ...
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in_array multiple values

... answered Sep 24 '11 at 23:51 Mark ElliotMark Elliot 65.9k1818 gold badges132132 silver badges155155 bronze badges ...
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Find intersection of two nested lists?

... If you want: c1 = [1, 6, 7, 10, 13, 28, 32, 41, 58, 63] c2 = [[13, 17, 18, 21, 32], [7, 11, 13, 14, 28], [1, 5, 6, 8, 15, 16]] c3 = [[13, 32], [7, 13, 28], [1,6]] Then here is your solution for Python 2: c3 = [filter(lambda x: x in c1, sublist) for sublis...