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awk without printing newline
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answered Jan 7 '10 at 16:56
CodeRainCodeRain
5,18444 gold badges2323 silver badges3232 bronze badges
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Find the most frequent number in a numpy vector
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edited Aug 5 at 18:08
B. Willems
1533 bronze badges
answered Jun 6 '11 at 13:01
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Using [UIColor colorWithRed:green:blue:alpha:] doesn't work with UITableView seperatorColor?
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You need to divide by 255.0
Because I hardly ever use values between 1.0 and 0.0, I created a very simple UIColor category that does the messy looking division by itself: (from http://github.com/Jon889/JPGeneral)
//.h file
@interface UIColor (JPExtr...
Have a reloadData for a UITableView animate when changing
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402
Actually, it's very simple:
[_tableView reloadSections:[NSIndexSet indexSetWithIndex:0] withRo...
Is there a NumPy function to return the first index of something in an array?
...mensions and it contained your item at two locations then
array[itemindex[0][0]][itemindex[1][0]]
would be equal to your item and so would
array[itemindex[0][1]][itemindex[1][1]]
numpy.where
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Why am I seeing “TypeError: string indices must be integers”?
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answered May 20 '11 at 21:16
TamásTamás
42.9k1111 gold badges9090 silver badges118118 bronze badges
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SSL Connection / Connection Reset with IISExpress
I'm using the new Visual Studio 2013 with IISExpress for the first time (previously used ASP.net Development server on VS2010). I'm running into issues trying to debug my project.
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What's the fastest way to convert String to Number in JavaScript?
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There are 4 ways to do it as far as I know.
Number(x);
parseInt(x, 10);
parseFloat(x);
+x;
By this quick test I made, it actually depends on browsers.
http://jsperf.com/best-of-string-to-number-conversion/2
Implicit marked the fastest on 3 browsers, but it makes the code hard to read… S...
How to change text transparency in HTML/CSS?
I'm very new to HTML/CSS and I'm trying to display some text as like 50% transparent. So far I have the HTML to display the text with full opacity
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Why is the shovel operator (
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Proof:
a = 'foo'
a.object_id #=> 2154889340
a << 'bar'
a.object_id #=> 2154889340
a += 'quux'
a.object_id #=> 2154742560
So << alters the original string rather than creating a new one. The reason for this is that in ruby a += b is syntactic short...