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Remove a HTML tag but keep the innerHtml
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$('b').contents().unwrap();
This selects all <b> elements, then uses .contents() to target the text content of the <b>, then .unwrap() to remove its parent <b> element.
For the greatest performance, always...
What is the Ruby (spaceship) operator?
What is the Ruby <=> (spaceship) operator? Is the operator implemented by any other languages?
6 Answers
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How do you convert a byte array to a hexadecimal string, and vice versa?
How can you convert a byte array to a hexadecimal string, and vice versa?
45 Answers
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Get the cartesian product of a series of lists?
How can I get the Cartesian product (every possible combination of values) from a group of lists?
13 Answers
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What does ** (double star/asterisk) and * (star/asterisk) do for parameters?
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The *args and **kwargs is a common idiom to allow arbitrary number of arguments to functions as described in the section more on defining functions in the Python documentation.
The *args will give you all function parameters as a tuple:
def foo(*args):
for a in args:
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How do I compare two strings in Perl?
...erlop. Use lt, gt, eq, ne, and cmp as appropriate for string comparisons:
Binary eq returns true if the left argument is stringwise equal to the right argument.
Binary ne returns true if the left argument is stringwise not equal to the right argument.
Binary cmp returns -1, 0, or 1 depending on whe...
Difference between MEAN.js and MEAN.io
I wanted to use the MEAN JavaScript Stack, but I noticed that there are two different stacks with either their own website and installation methods: mean.js and mean.io. So I came up asking myself this question: "Which one do I use?".
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Elegant way to invert a map in Scala
...e inverted value->key lookups. I was looking for a simple way to do this, but came up with only:
10 Answers
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python list by value not by reference [duplicate]
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As answered in the official Python FAQ:
b = a[:]
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Calculate difference in keys contained in two Python dictionaries
Suppose I have two Python dictionaries - dictA and dictB . I need to find out if there are any keys which are present in dictB but not in dictA . What is the fastest way to go about it?
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