大约有 48,000 项符合查询结果（耗时：0.0364秒） [XML]
Approximate cost to access various caches and main memory?
...--------------------------
0.1 ns - NOP
0.3 ns - XOR, ADD, SUB
0.5 ns - CPU L1 dCACHE reference (1st introduced in late 80-ies )
0.9 ns - JMP SHORT
1 ns - speed-of-light (a photon) travel a 1 ft (30.5cm) distance -- will st...
深入理解 x86/x64 的中断体系 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术
...-----------------------------
printmsg:
mov ah, 0x0e
xor bh, bh
print_loop:
lodsb
test al,al
jz done
int 0x10
jmp print_loop
done:
ret
old_IVT dw 0 ; limit of I...
What does multicore assembly language look like?
...it_len, %ecx
mov $init, %esi
mov 0x1000, %edi
rep movsb
.code16
init:
xor %ax, %ax
mov %ax, %ds
/* Do stuff. */
hlt
.equ init_len, . - init
Using a linker script is another possibility.
The delay loops are an annoying part to get working: there is no super simple way to do such sl...
Why does GCC generate such radically different assembly for nearly the same C code?
...fast_trunc_one() - register names and everything.
Notice that there are no xors in the assembly for fast_trunc_one(). That's what gave it away for me.
How so?
Step 1: sign = -sign
First, let's take a look at the sign variable. Since sign = i & 0x80000000;, there are only two possible values th...
Why is x86 ugly? Why is it considered inferior when compared to others? [closed]
...
Consider the operation "a=b/c" x86 would implement this as
mov eax,b
xor edx,edx
div dword ptr c
mov a,eax
As an additional bonus of the div instruction edx will contain the remainder.
A RISC processor would require first loading the addresses of b and c, loading b and c from memory to ...
Why does this loop produce “warning: iteration 3u invokes undefined behavior” and output more than 4
...i_escape 0x10,0x6,0x2,0x75,0x78
.cfi_escape 0x10,0x3,0x2,0x75,0x74
xorl %edi, %edi
subl $24, %esp
call ___main
L4:
movl %edi, (%esp)
movl $__ZSt4cout, %ecx
call __ZNSolsEi
movl %eax, %esi
movl (%eax), %eax
subl $4, %esp
movl -...
Programmer Puzzle: Encoding a chess board state throughout a game
...not to, at least in part, resemble a starting position.
So what you do is XOR the 256 bit current board position with a 256 bit starting position and then encode that (using Huffman coding or, say, some method of run length encoding). Obviously this will be very efficient to start with (64 0s proba...
How to run a program without an operating system?
....S
.code16
.text
.global mystart
mystart:
ljmp $0, $.setcs
.setcs:
xor %ax, %ax
mov %ax, %ds
mov %ax, %es
mov %ax, %ss
mov $__stack_top, %esp
cld
call main
linker.ld
ENTRY(mystart)
SECTIONS
{
. = 0x7c00;
.text : {
entry.o(.text)
*(.text)
*(.data)
...
Relational table naming convention [closed]
... description or whatever.
That's right. Either user_product_description xor product_description will be correct, based on the above. It is not to differentiate it from other xxxx_descriptions, but it is to give the name a sense of where it belongs, the prefix being the parent table.
What abo...
通信连接组件 · App Inventor 2 中文网
...验类型)
在字节列表末尾追加校验，返回新列表：SUM8、XOR8、CRC8 追加 1 个字节，CRC16 追加 2 个，CRC32 追加 4 个。
CRC16-MODBUS 按协议规定低字节在前，其余按「高位优先」属性。校验类型见计算校验。
例：01 03 00 00 00 0A 追加 CRC1...