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get string value from HashMap depending on key name
...t: you edited your question with the following:
I'm expecting to see a String, such as "ABC" or "DEF" as that is what I put in there initially, but if I do a System.out.println() I get something like java.lang.string#F0454
Sorry, I'm not too familiar with maps as you can probably guess ;)
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How to control the line spacing in UILabel
...Style = NSMutableParagraphStyle()
paragraphStyle.lineSpacing = 40
let attrString = NSMutableAttributedString(string: "Swift Answer")
attrString.addAttribute(.paragraphStyle, value:paragraphStyle, range:NSMakeRange(0, attrString.length))
var tableViewCell = NSTableCellView()
tableViewCell.textField...
warning: incompatible implicit declaration of built-in function ‘xyz’
...n-* flags if possible.
Instead of stdlib.h, you should try:
#include <string.h>
That's where strcpy and strncpy are defined, at least according to the strcpy(2) man page.
The exit function is defined in stdlib.h, though, so I don't know what's going on there.
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Limit the length of a string with AngularJS
...max (integer) - max length of the text, cut to this number of chars,
tail (string, default: ' …') - add this string to the input
string if the string was cut.
Another solution: http://ngmodules.org/modules/angularjs-truncate (by @Ehvince)
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PHP Replace last occurrence of a String in a String?
Anyone know of a very fast way to replace the last occurrence of a string with another string in a string?
14 Answers
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How should I copy Strings in Java?
...kup variable still contains the original value "hello" (this is because of String's immutability right?).
5 Answers
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SQL query to group by day
...er (from Jon Bright):
GROUP BY date(datefield)
For Oracle:
GROUP BY to_char(datefield, 'yyyy-mm-dd')
or faster (from IronGoofy):
GROUP BY trunc(created);
For Informix (by Jonathan Leffler):
GROUP BY date_column
GROUP BY EXTEND(datetime_column, YEAR TO DAY)
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Remove Last Comma from a string
..., etc) and the * means 0 or more
The $ at the end signifies the end of the string
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Append a dictionary to a dictionary [duplicate]
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You can do
orig.update(extra)
or, if you don't want orig to be modified, make a copy first:
dest = dict(orig) # or orig.copy()
dest.update(extra)
Note that if extra and orig have overlapping keys, the final value will be taken from extra. For...
Create an Array of Arraylists
... Any reason this would be preferable over @kelvincer Answer (ArrayList<String>[] group = new ArrayList[4])? What extra good doe sthe cast do?
– cellepo
Mar 22 '16 at 21:12
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