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Check variable equality against a list of values
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You could use an array and indexOf:
if ([1,3,12].indexOf(foo) > -1)
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Get index of array element faster than O(n)
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fastest if the array is very long
– Kevin
Nov 19 '12 at 19:13
18
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How to check if one of the following items is in a list?
I'm trying to find a short way to see if any of the following items is in a list, but my first attempt does not work. Besides writing a function to accomplish this, is the any short way to check if one of multiple items is in a list.
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In Jinja2, how do you test if a variable is undefined?
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From the Jinja2 template designer documentation:
{% if variable is defined %}
value of variable: {{ variable }}
{% else %}
variable is not defined
{% endif %}
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Cron job every three days
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Run it every three days...
0 0 */3 * *
How about that?
If you want it to run on specific days of the month, like the 1st, 4th, 7th, etc... then you can just have a conditional in your script that checks for the current day of the month.
if (((date('j') - 1) % 3))
exit();
or...
水果vs蔬菜智能分类器 - EdgeML图像识别项目 · App Inventor 2 中文网
...目实现步骤
第一步：了解 Personal Image Classifier (PIC)
PIC扩展的主要功能：
与传统机器学习的区别：
第二步：使用 PIC 训练自定义模型
1. 数...
How to break out from a ruby block?
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Use the keyword next. If you do not want to continue to the next item, use break.
When next is used within a block, it causes the block to exit immediately, returning control to the iterator method, which may then begin a new iteration by invokin...
How do I get indices of N maximum values in a NumPy array?
...]: array([4, 3, 1])
This involves a complete sort of the array. I wonder if numpy provides a built-in way to do a partial sort; so far I haven't been able to find one.
If this solution turns out to be too slow (especially for small n), it may be worth looking at coding something up in Cython.
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How to use Regular Expressions (Regex) in Microsoft Excel both in-cell and loops
.... [a-z] matches any single lower case letter of the alphabet.
() Groups different matches for return purposes. See examples below.
{} Multiplier for repeated copies of pattern defined before it.
E.g. [a]{2} matches two consecutive lower case letter a: aa
E.g. [a]{1,3} matches at least one and ...
Flatten nested dictionaries, compressing keys
...ems = []
for k, v in d.items():
new_key = parent_key + sep + k if parent_key else k
if isinstance(v, collections.MutableMapping):
items.extend(flatten(v, new_key, sep=sep).items())
else:
items.append((new_key, v))
return dict(items)
>>&g...