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Python list subtraction operation
...
Use a list comprehension:
[item for item in x if item not in y]
If you want to use the - infix syntax, you can just do:
class MyList(list):
def __init__(self, *args):
super(MyList, self).__init__(args)
def __sub__(self, other):
return self.__c...
Limit Decimal Places in Android EditText
...anage your finances. I'm using an EditText Field where the user can specify an amount of money.
37 Answers
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What are deferred objects?
...nd new feature. I have no idea how they work, and I think it would be good if StackOverflow had this question well explained for those who will ask about it in the future.
– user113716
Feb 1 '11 at 19:13
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How to compare two strings in dot separated version format in Bash?
...that doesn't require any external utilities:
#!/bin/bash
vercomp () {
if [[ $1 == $2 ]]
then
return 0
fi
local IFS=.
local i ver1=($1) ver2=($2)
# fill empty fields in ver1 with zeros
for ((i=${#ver1[@]}; i<${#ver2[@]}; i++))
do
ver1[i]=0
done
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How to convert an xml string to a dictionary?
...:
def __init__(self, aList):
for element in aList:
if element:
# treat like dict
if len(element) == 1 or element[0].tag != element[1].tag:
self.append(XmlDictConfig(element))
# treat like list
...
Why doesn't Python have a sign function?
...;>> math.copysign(1, -4)
-1.0
>>> math.copysign(1, 3)
1.0
If you get sick of passing two whole arguments, you can implement sign this way, and it will still be compatible with the IEEE stuff mentioned by others:
>>> sign = functools.partial(math.copysign, 1) # either of th...
Python - Check If Word Is In A String
I'm working with Python v2, and I'm trying to find out if you can tell if a word is in a string.
11 Answers
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How do I check if there are duplicates in a flat list?
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Use set() to remove duplicates if all values are hashable:
>>> your_list = ['one', 'two', 'one']
>>> len(your_list) != len(set(your_list))
True
share
|...
How to find all combinations of coins when given some dollar value
...rful book Generatingfunctionology: math.upenn.edu/~wilf/DownldGF.html) and if you mean an expression like (1+√5)^n, it takes Ω(log n) time to compute, not constant time.
– ShreevatsaR
Jul 10 '09 at 18:33
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Replace values in list using Python [duplicate]
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Build a new list with a list comprehension:
new_items = [x if x % 2 else None for x in items]
You can modify the original list in-place if you want, but it doesn't actually save time:
items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
for index, item in enumerate(items):
if not (item ...