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What is “point free” style (in Functional Programming)?

...you specify the arguments explicitly): sum (x:xs) = x + (sum xs) sum [] = 0 Point-free (sum doesn't have any explicit arguments - it's just a fold with + starting with 0): sum = foldr (+) 0 Or even simpler: Instead of g(x) = f(x), you could just write g = f. So yes: It's closely related to c...
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Fancybox doesn't work with jQuery v1.9.0 [ f.browser is undefined / Cannot read property 'msie' ]

Fancybox breaks with the new jQuery v1.9.0. 4 Answers 4 ...
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Counting the Number of keywords in a dictionary in python

... | edited Feb 7 '10 at 5:11 answered Feb 6 '10 at 7:41 ...
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PHP function to make slug (URL string)

... | edited Jul 17 '18 at 20:04 leoap 1,48833 gold badges2222 silver badges2929 bronze badges answered Ju...
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How do I draw a shadow under a UIView?

...eeds to happen after CGContextSetShadow(currentContext, CGSizeMake(-15, 20), 5); but before CGContextRestoreGState(currentContext); So if you want the superclass's drawRect: to be 'wrapped' in a shadow, then how about if you rearrange your code like this? - (void)drawRect:(CGRect)rect { ...
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Regex to replace everything except numbers and a decimal point

... Use this: document.getElementById(target).value = newVal.replace(/[^0-9.]/g, ""); share | improve this answer | follow | ...
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jQuery select all except first

... $("div.test:not(:first)").hide(); or: $("div.test:not(:eq(0))").hide(); or: $("div.test").not(":eq(0)").hide(); or: $("div.test:gt(0)").hide(); or: (as per @Jordan Lev's comment): $("div.test").slice(1).hide(); and so on. See: http://api.jquery.com/first-selector/ http...
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Is there a float input type in HTML5?

... +50 The number type has a step value controlling which numbers are valid (along with max and min), which defaults to 1. This value is also...
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How add “or” in switch statements?

... | edited May 11 '09 at 14:56 answered May 11 '09 at 14:51 ...
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Lambda function in list comprehensions

... calls it ten times. The second one doesn't call the function. It creates 10 different lambda functions. It puts all of those in a list. To make it equivalent to the first you need: [(lambda x: x*x)(x) for x in range(10)] Or better yet: [x*x for x in range(10)] ...