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Remove all occurrences of a value from a list?
... The code for habnabit's suggestion looks like this: [y for y in x if y != 2]
– coredumperror
Apr 22 '13 at 22:12
...
How does java do modulus calculations with negative numbers?
...umbers are in use - some languages use one definition and some the other.
If you want to get a negative number for negative inputs then you can use this:
int r = x % n;
if (r > 0 && x < 0)
{
r -= n;
}
Likewise if you were using a language that returns a negative number on a neg...
How to find list intersection?
...
If order is not important and you don't need to worry about duplicates then you can use set intersection:
>>> a = [1,2,3,4,5]
>>> b = [1,3,5,6]
>>> list(set(a) & set(b))
[1, 3, 5]
...
Permutations in JavaScript?
...
If you notice, the code actually splits the chars into an array prior to do any permutation, so you simply remove the join and split operation
var permArr = [],
usedChars = [];
function permute(input) {
var i, c...
MongoDB atomic “findOrCreate”: findOne, insert if nonexistent, but do not update
...the title says, I want to perform a find (one) for a document, by _id, and if doesn't exist, have it created, then whether it was found or was created, have it returned in the callback.
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Divide a number by 3 without using *, /, +, -, % operators
...gt;> 2, sum);
num = add(num >> 2, num & 3);
}
if (num == 3)
sum = add(sum, 1);
return sum;
}
As Jim commented this works, because:
n = 4 * a + b
n / 3 = a + (a + b) / 3
So sum += a, n = a + b, and iterate
When a == 0 (n < 4), sum += floor(n / 3); i....
JavaScript is in array
...
Try this:
if(blockedTile.indexOf("118") != -1)
{
// element found
}
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follo...
not None test in Python [duplicate]
...
if val is not None:
# ...
is the Pythonic idiom for testing that a variable is not set to None. This idiom has particular uses in the case of declaring keyword functions with default parameters. is tests identity in Pyt...
One-line list comprehension: if-else variants
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x if y else z is the syntax for the expression you're returning for each element. Thus you need:
[ x if x%2 else x*100 for x in range(1, 10) ]
The confusion arises from the fact you're using a filter in the first example, bu...
Javascript - remove an array item by value [duplicate]
...,3,56,6,8,90],
id_tag = 90,
position = tag_story.indexOf(id_tag);
if ( ~position ) tag_story.splice(position, 1);
P.S. For an explanation of that cool ~ tilde shortcut, see this post:
Using a ~ tilde with indexOf to check for the existence of an item in an array.
Note: IE < 9 does ...