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How can I verify if one list is a subset of another?
I need to verify if a list is a subset of another - a boolean return is all I seek.
15 Answers
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Get the index of the nth occurrence of a string?
...t of n method invocations - you won't actually be checking any case twice, if you think about it. (IndexOf will return as soon as it finds the match, and you'll keep going from where it left off.)
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It is more efficient to use if-return-return or if-else-return?
Suppose I have an if statement with a return . From the efficiency perspective, should I use
8 Answers
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What is the correct syntax for 'else if'?
...om 2.6.4 to 3.1.1. Everything has gone fine until I tried to use the 'else if' statement. The interpreter gives me a syntax error after the 'if' in 'else if' for a reason I can't seem to figure out.
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Check if a file exists with wildcard in shell script [duplicate]
I'm trying to check if a file exists, but with a wildcard. Here is my example:
21 Answers
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Interview question: Check if one string is a rotation of other string [closed]
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First make sure s1 and s2 are of the same length. Then check to see if s2 is a substring of s1 concatenated with s1:
algorithm checkRotation(string s1, string s2)
if( len(s1) != len(s2))
return false
if( substring(s2,concat(s1,s1))
return true
return false
end
In Java:
bool...
Using jQuery to compare two arrays of Javascript objects
I have two arrays of JavaScript Objects that I'd like to compare to see if they are the same. The objects may not (and most likely will not) be in the same order in each array. Each array shouldn't have any more than 10 objects. I thought jQuery might have an elegant solution to this problem, but I ...
How do I query if a database schema exists
... our build process we run a database update script as we deploy code to 4 different environments. Further, since the same query will get added to until we drop a release into production it has to be able to run multiple times on a given database. Like this:
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VBA - how to conditionally skip a for loop iteration
...is test for a certain condition in the loop and skip to the next iteration if true:
6 Answers
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Fastest way to flatten / un-flatten nested JSON objects
...implementation:
Object.unflatten = function(data) {
"use strict";
if (Object(data) !== data || Array.isArray(data))
return data;
var regex = /\.?([^.\[\]]+)|\[(\d+)\]/g,
resultholder = {};
for (var p in data) {
var cur = resultholder,
prop = "",
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