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Rails 3: Get Random Record
So, I've found several examples for finding a random record in Rails 2 -- the preferred method seems to be:
14 Answers
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How to cast an Object to an int
How can I cast an Object to an int in java?
19 Answers
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Do we need semicolon at the end? [duplicate]
I missed semicolons in some of the places in my JavaScript, but its not throwing error in any of the browsers. Is the ; at the end needed?
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How to set SQL Server connection string?
I'm developing a simple C# application, I'd like to know this: When I connect my application to SQL Server on my PC, I know the connection string (server name, password etc.), but when I connect it to another PC, the SQL Server connection string is different. Is there a common account in SQL Server ...
How do I list all remote branches in Git 1.7+?
I've tried git branch -r , but that only lists remote branches that I've tracked locally. How do I find the list of those that I haven't? (It doesn't matter to me whether the command lists all remote branches or only those that are untracked.)
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What Ruby IDE do you prefer? [closed]
I've been using Eclipse with RDT (not RadRails) a lot lately, and I'm quite happy with it, but I'm wondering if you guys know any decent alternatives. I know NetBeans also supports Ruby these days, but I'm not sure what it has to offer over Eclipse.
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Implications of foldr vs. foldl (or foldl')
Firstly, Real World Haskell , which I am reading, says to never use foldl and instead use foldl' . So I trust it.
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Parsing a comma-delimited std::string [duplicate]
If I have a std::string containing a comma-separated list of numbers, what's the simplest way to parse out the numbers and put them in an integer array?
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How To Accept a File POST
I'm using asp.net mvc 4 webapi beta to build a rest service. I need to be able to accept POSTed images/files from client applications. Is this possible using the webapi? Below is how action I am currently using. Does anyone know of an example how this should work?
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How to make zsh run as a login shell on Mac OS X (in iTerm)?
When zsh is set as a login shell on Mac OS X, when it is started by iTerm, zsh doesn't consider that it's being run as a login shell, although it's started as ‘-zsh’ (‘-’ is put as the first character of arg[0]) which is supposed to mean that it should start as a login shell.
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