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How is “=default” different from “{}” for default constructor and destructor?
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105
This is a completely different question when asking about constructors than destructors.
If yo...
SSL Connection / Connection Reset with IISExpress
I'm using the new Visual Studio 2013 with IISExpress for the first time (previously used ASP.net Development server on VS2010). I'm running into issues trying to debug my project.
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Understanding how recursive functions work
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107
I think the confusion is stemming from thinking of it as "the same function" being called many ...
What's the fastest way to convert String to Number in JavaScript?
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There are 4 ways to do it as far as I know.
Number(x);
parseInt(x, 10);
parseFloat(x);
+x;
By this quick test I made, it actually depends on browsers.
http://jsperf.com/best-of-string-to-number-conversion/2
Implicit marked the fastest on 3 browsers, but it makes the code hard to read… S...
Have a reloadData for a UITableView animate when changing
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402
Actually, it's very simple:
[_tableView reloadSections:[NSIndexSet indexSetWithIndex:0] withRo...
printf() formatting for hex
...hy when printing hex as an 8 digit number with leading zeros, does this %#08X Not display the same result as 0x%08X ?
3 ...
Detect Windows version in .net
...---+
| Windows 95 | Win32Windows | 4 | 0 |
| Windows 98 | Win32Windows | 4 | 10 |
| Windows Me | Win32Windows | 4 | 90 |
| Windows NT 4.0 | Win32NT | 4 ...
Fastest way to iterate over all the chars in a String
...se now Java will store strings as byte[] by default.
SECOND UPDATE: As of 2016-10-25, on my AMDx64 8core and source 1.8, there is no difference between using 'charAt' and field access. It appears that the jvm is sufficiently optimized to inline and streamline any 'string.charAt(n)' calls.
THIRD UPDA...
深入理解 x86/x64 的中断体系 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术
...ddress mode，关于实模式请详见文章：http://www.mouseos.com/arch/001.html
processor 执行的第一条指针在 0xFFFFFFF0 处，这个地址经过 North Bridge（北桥）和 South ridge（南桥）芯片配合解码，最终会访问到固化的 ROM 块，同时，经过别名机制映...
Why is the shovel operator (
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Proof:
a = 'foo'
a.object_id #=> 2154889340
a << 'bar'
a.object_id #=> 2154889340
a += 'quux'
a.object_id #=> 2154742560
So << alters the original string rather than creating a new one. The reason for this is that in ruby a += b is syntactic short...