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How to make a phone call using intent in Android?
...Your Phone_number"));
startActivity(intent);
Permission in Manifest:
<uses-permission android:name="android.permission.CALL_PHONE" />
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How to print full stack trace in exception?
... in the stack traces, not necessarily the messages. Or I want it as a List<string> not a single string.
– Zar Shardan
Sep 9 '19 at 9:28
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How to overload functions in javascript?
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There are multiple aspects to argument overloading in Javascript:
Variable arguments - You can pass different sets of arguments (in both type and quantity) and the function will behave in a way that matches the arguments passed to it.
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How to make EditText not editable through XML in Android?
...sily to that! I do have one question. Does this in any way change the default values needed by KeyListener, like setFocusable() because the doc says that the default implementation might be changed if changed.
– Andy
Jun 26 '12 at 18:20
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How to describe “object” arguments in jsdoc?
.../
For objects whose values are all the same type
/**
* @param {Object.<string, number>} dict
*/
The first type (string) documents the type of the keys which in JavaScript is always a string or at least will always be coerced to a string. The second type (number) is the type of the value...
Rails: How can I set default values in ActiveRecord?
How can I set default value in ActiveRecord?
27 Answers
27
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How to check if one of the following items is in a list?
...g a function to accomplish this, is the any short way to check if one of multiple items is in a list.
14 Answers
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restrict edittext to single line
...nd refer for android:inputType With your example, below will give this result:
<EditText
android:id="@+id/searchbox"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:maxLines="1"
android:inputType="text"
android:scrollHorizontally="true...
How to get item's position in a list?
...a generator...
>>> (i for i,x in enumerate(testlist) if x == 1)
<generator object at 0x6b508>
>>> for i in (i for i,x in enumerate(testlist) if x == 1):
... print i
...
0
5
7
and niftily enough, we can assign that to a variable, and use it from there...
>>> ...
How is it possible to declare nothing inside main() in C++ and yet have a working application after
...or during the first initialization of an std::ios_base::Init object. And <iostream> is guaranteed to behave "as if" it contained an instance of an std::ios_base_Init object at namespace scope.
– James Kanze
Jul 8 '13 at 15:30
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