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How can I force a long string without any blank to be wrapped?
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It's supported only in IE, Safari, and FF3.1 (alpha).
– Adam Bellaire
Jan 31 '09 at 17:21
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How to reference constants in EL?
...e.YourConstants" %>
This will under the covers be imported via ImportHandler#importClass() and be available as ${YourConstants.FOO}.
Note that all java.lang.* classes are already implicitly imported and available like so ${Boolean.TRUE} and ${Integer.MAX_VALUE}. This only requires a more recen...
Read and parse a Json File in C#
I have spent the best part of two days "faffing" about with code samples and etc., trying to read a very large JSON file into an array in c# so I can later split it up into a 2d array for processing.
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get dictionary key by value
...types.FirstOrDefault(x => x.Value == "one").Key;
If values are unique and are inserted less frequently than read, then create an inverse dictionary where values are keys and keys are values.
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Uncaught SyntaxError: Unexpected token with JSON.parse
... is it not an Array? Why is it an object. Objects start with { and arrays start with [? or am i false here
– user2396641
Sep 4 '16 at 17:20
4
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Best implementation for hashCode method for a collection
...ins there why the approach is good.
A short version
Create a int result and assign a non-zero value.
For every field f tested in the equals() method, calculate a hash code c by:
If the field f is a boolean:
calculate (f ? 0 : 1);
If the field f is a byte, char, short or int: calculate (int)f;
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No appenders could be found for logger(log4j)?
...valid.
That guide will give you some information about how to use loggers and appenders.
Just to get you going you have two simple approaches you can take.
First one is to just add this line to your main method:
BasicConfigurator.configure();
Second approach is to add this standard log4j.pro...
Passing base64 encoded strings in URL
...would need to url-encode it, since base64 strings can contain the "+", "=" and "/" characters which could alter the meaning of your data - look like a sub-folder.
Valid base64 characters are below.
ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=
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RuntimeWarning: invalid value encountered in divide
...is trying to "divide by zero" or "divide by NaN". If you are aware of that and don't want it to bother you, then you can try:
import numpy as np
np.seterr(divide='ignore', invalid='ignore')
For more details see:
http://docs.scipy.org/doc/numpy/reference/generated/numpy.seterr.html
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How to match “anything up until this sequence of characters” in a regular expression?
...s possible to satisfy.
When using .+?, instead of matching all at once and going back for
other conditions (if any), the engine will match the next characters by
step until the subsequent part of the regex is matched (again if any).
This is the un-greedy, meaning match the fewest possi...