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Grep characters before and after match?

... 3 characters before and 4 characters after $> echo "some123_string_and_another" | grep -o -P '.{0,3}string.{0,4}' 23_string_and share | improve this answer | ...
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Encode URL in JavaScript?

... 2847 Check out the built-in function encodeURIComponent(str) and encodeURI(str). In your case, thi...
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jQuery get value of select onChange

...alue ); }); <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <select> <option value="1">One</option> <option value="2">Two</option> </select> You can also reference with onchange event- ...
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How to get the first column of a pandas DataFrame as a Series?

...>>> import pandas as pd >>> df = pd.DataFrame({'x' : [1, 2, 3, 4], 'y' : [4, 5, 6, 7]}) >>> df x y 0 1 4 1 2 5 2 3 6 3 4 7 >>> s = df.ix[:,0] >>> type(s) <class 'pandas.core.series.Series'> >>> ================================...
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Logical XOR operator in C++?

... answered Oct 20 '09 at 19:03 Greg HewgillGreg Hewgill 783k167167 gold badges10841084 silver badges12221222 bronze badges ...
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C++常用排序算法汇总 - C/C++ - 清泛网 - 专注C/C++及内核技术

...**************************** * 简单选择排序 * 稳定排序,O{n^2} ~ O{n^2} * 从首位开始,循环一次找出一个比首位小的值,交换 * * https://www.tsingfun.com ************************************/ #include<stdio.h> #include<stdlib.h> /* 第一种形式的选...
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Invalid syntax when using “print”? [duplicate]

... 232 That is because in Python 3, they have replaced the print statement with the print function. ...
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Python - Count elements in list [duplicate]

... | edited Dec 4 '14 at 23:26 Charlie 6,5134545 silver badges5050 bronze badges answered Nov 9 '10 at ...
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How do we determine the number of days for a given month in python [duplicate]

...ulate the number of days for a given month in python. If a user inputs Feb 2011 the program should be able to tell me that Feb 2011 has 28 days. Could any one tell me which library I should use to determine the length of a given month. ...
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Iterating over a numpy array

...think you're looking for the ndenumerate. &gt;&gt;&gt; a =numpy.array([[1,2],[3,4],[5,6]]) &gt;&gt;&gt; for (x,y), value in numpy.ndenumerate(a): ... print x,y ... 0 0 0 1 1 0 1 1 2 0 2 1 Regarding the performance. It is a bit slower than a list comprehension. X = np.zeros((100, 100, 100)) %...