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Is PHP's count() function O(1) or O(n) for arrays?
...TENT() is just a sanity check on the array github.com/php/php-src/blob/PHP-5.3/Zend/zend_hash.c#L51
– John Carter
Apr 20 '13 at 22:04
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C++及Windows异常处理(try，catch; __try,__finally, __except) - C/C++ - ...
...是如上的三个关键字，注意C++中throw，catch之后没有Java等语言中的finally。
Q: 为何C++不提供“finally”结构？
A: 因为C++提供了另一种机制，完全可以取代finally，而且这种机制几乎总要比finally工作得更好：就是——“分配资源即...
ZMQ: 基本原理 - 开源 & Github - 清泛网 - 专注C/C++及内核技术
...用的分布式数据库。而且这儿的名字解析服务的需求似乎完美的匹配DNS所提供的特性。
像DNS这样以松散地一致性分布式数据库方式存储名字的设计结果应当引起注意，比如拓扑应该是长期存活并且很少更改条目，以确保DNS缓冲...
ZMQ: 基本原理 - 开源 & Github - 清泛网 - 专注C/C++及内核技术
...用的分布式数据库。而且这儿的名字解析服务的需求似乎完美的匹配DNS所提供的特性。
像DNS这样以松散地一致性分布式数据库方式存储名字的设计结果应当引起注意，比如拓扑应该是长期存活并且很少更改条目，以确保DNS缓冲...
Weighted random numbers
...levant lines (/usr/include/c++/5/bits/random.tcc on my Ubuntu 16.04 + GCC 5.3 install):
template<typename _IntType>
void
discrete_distribution<_IntType>::param_type::
_M_initialize()
{
if (_M_prob.size() < 2)
{
_M_prob.clear();
ret...
Run php script as daemon process
...
JonathanJonathan
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搭建高可用mongodb集群（一）——配置mongodb - 大数据 & AI - 清泛网 - 专...
...据库当中最像关系数据库的。支持类似于面向对象的查询语言，几乎可以实现类似关系数据库单表查询的绝大部分功能，而且还支持对数据建立索引。所以这个非常方便，我们可以用sql操作MongoDB，从关系型数据库迁移过来，开...
in_array multiple values
...ore complex comparison operations between array elements AND you're on PHP 5.3, you might also think about something like the following:
<?php
// First Array To Compare
$a1 = array('foo','bar','c');
// Target Array
$b1 = array('foo','bar');
// Evaluation Function - we pass guard and target a...
What is the entry point of swift code execution?
...
In Swift 5.3 there is a new @main attribute which lets you control where your entry point is in your project rather than just main.swift. There can only be one main entry and you can't have a main.swift file and a an attribute @main. ...
Generating a UUID in Postgres for Insert statement?
...ch more likely than the chance of immediate collision in v4, which is 1 in 5.3e36. Obviously the longer you generate v4 UUIDs the more likely a collision becomes, which is not true of v1, but you'd have to generate 1.52 billion v4 UUIDs before the probability of collision exceeded that of node's v1 ...