大约有 47,000 项符合查询结果（耗时：0.0397秒） [XML]
Is there a unique Android device ID?
...d devices have a unique ID, and if so, what is a simple way to access it using Java?
52 Answers
...
Check whether an input string contains a number in javascript
My end goal is to validate an input field. The input may be either alphabetic or numeric.
12 Answers
...
How do I UPDATE from a SELECT in SQL Server?
In SQL Server , it is possible to insert rows into a table with an INSERT.. SELECT statement:
35 Answers
...
print memory address of Python variable [duplicate]
How do I print the memory address of a variable in Python 2.7?
I know id() returns the 'id' of a variable or object, but this doesn't return the expected 0x3357e182 style I was expecting to see for a memory address.
I want to do something like print &x , where x is a C++ int variable for exam...
When to use next() and return next() in Node.js
Scenario : Consider the following is the part of code from a node web app.
5 Answers
5...
Select2 dropdown but allow new values by user?
...
For version 4+ check this answer below by Kevin Brown
In Select2 3.5.2 and below, you can use something like:
$(selector).select2({
minimumInputLength:1,
"ajax": {
data:function (term, page) {
return { term:term, page:page };
},
dataType:"json",
...
How do I map lists of nested objects with Dapper
I'm currently using Entity Framework for my db access but want to have a look at Dapper. I have classes like this:
7 Answer...
Instagram how to get my user id from username?
I'm in the process of embedding my image feed in my website using JSON, the URL needs my user id so I can retrieve this feed.
...
Sort objects in an array alphabetically on one property of the array
...
you would have to do something like this:
objArray.sort(function(a, b) {
var textA = a.DepartmentName.toUpperCase();
var textB = b.DepartmentName.toUpperCase();
return (textA < textB) ? -1 : (textA > textB) ? 1 : 0;
});
note: chang...
Delete duplicate records in SQL Server?
...
You can do this with window functions. It will order the dupes by empId, and delete all but the first one.
delete x from (
select *, rn=row_number() over (partition by EmployeeName order by empId)
from Employee
) x
where rn > 1;
Run it ...