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How to convert comma-delimited string to list in Python?
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edited Apr 18 '13 at 0:36
answered Oct 21 '11 at 1:35
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Why use Ruby's attr_accessor, attr_reader and attr_writer?
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750
You may use the different accessors to communicate your intent to someone reading your code, and...
GroupBy pandas DataFrame and select most common value
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How do I get user IP address in django?
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450
def get_client_ip(request):
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
i...
inserting characters at the start and end of a string
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answered Apr 8 '12 at 0:47
Mark ByersMark Byers
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How do I decode a string with escaped unicode?
...ouble searching for it. How can I decode a string with unicode from http\u00253A\u00252F\u00252Fexample.com to http://example.com with JavaScript? I tried unescape , decodeURI , and decodeURIComponent so I guess the only thing left is string replace.
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Node.js + Nginx - What now?
...ng like:
# the IP(s) on which your node server is running. I chose port 3000.
upstream app_yourdomain {
server 127.0.0.1:3000;
keepalive 8;
}
# the nginx server instance
server {
listen 80;
listen [::]:80;
server_name yourdomain.com www.yourdomain.com;
access_log /var/log/...
Why in Java 8 split sometimes removes empty strings at start of result array?
... in Java 7 and Java 8. The code is retrieved from grepcode, for version 7u40-b43 and 8-b132.
Java 7
public String[] split(CharSequence input, int limit) {
int index = 0;
boolean matchLimited = limit > 0;
ArrayList<String> matchList = new ArrayList<>();
Matcher m = ma...
How do I declare a 2d array in C++ using new?
...ize it using a loop, like this:
int** a = new int*[rowCount];
for(int i = 0; i < rowCount; ++i)
a[i] = new int[colCount];
The above, for colCount= 5 and rowCount = 4, would produce the following:
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Should one use < or
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The first is more idiomatic. In particular, it indicates (in a 0-based sense) the number of iterations. When using something 1-based (e.g. JDBC, IIRC) I might be tempted to use &lt;=. So:
for (int i=0; i &lt; count; i++) // For 0-based APIs
for (int i=1; i &lt;= count; i++) // For 1-ba...