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Find the similarity metric between two strings
... + ' ' * (len(w1) - len(w2))
return sum(1 if i == j else 0 for i, j in zip(w1, w2)) / float(len(w1))
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Eclipse error: “The import XXX cannot be resolved”
...s the hibernate3.jar. I don't know why it was not well extracted from the .zip, maybe corrupt. A good way to check if jars are corrupt or not is navigating through their tree structure in "Project Explorer" in Eclipse: if you can't expand a jar node probably it's corrupt. I've seen that having corru...
外媒评本轮科技泡沫：创业公司首当其冲 九成将消失 - 资讯 - 清泛网 - 专注...
...容以及各种棘手的问题为依据，对私营公司进行投资——把它们当作是上市公司。
总之，越来越多的日常投资者正暴露给后期私营科技公司，无论结果是好还是坏。据博伊德介绍，作为富达国际旗下最大的基金之一，Fidelity Cont...
The project cannot be built until the build path errors are resolved.
...nd the information:
http://crunchify.com/cannot-be-read-or-is-not-a-valid-zip-file-how-to-fix-maven-build-path-error-with-corrupted-jar-file/
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Split list into smaller lists (split in half)
...this function in a loop, and the lengths vary. In other words: for i,j in zip(list,lengths): print(split(i,j)). The list and lengths lists have the same length. j is alternating: 5,4,5,4,5, and the split function works on the first two alternations, ie it splits the first i of list by 5 and 4, BU...
Python glob multiple filetypes
...3', 'flac', 'wma']
chars = ''.join('[{}]'.format(''.join(set(c))) for c in zip(*exts))
mask = mask_base + chars + ('*' if len(set(len(e) for e in exts)) > 1 else '')
print(mask) # music/*/*.[fmw][plm][3a]*
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month name to month number and vice versa in python
... you can do the same thing this way: month_cal = dict((v,k) for v,k in zip(calendar.month_abbr[1:], range(1, 13))), and then month_cal[shortMonth]
– Matt W.
Jul 12 '18 at 17:29
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Eclipse compilation error: The hierarchy of the type 'Class name' is inconsistent
... Archive for required library in project cannot be read or is not a valid ZIP file
So instead I added them as "External Jars". That helped and all compilation problems were no more!
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Get the current script file name
...on('bob.php')); // string(3) "bob"
var_dump(chopExtension('bob.i.have.dots.zip')); // string(15) "bob.i.have.dots"
Using standard string library functions is much quicker, as you'd expect.
function chopExtension($filename) {
return substr($filename, 0, strrpos($filename, '.'));
}
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Find files and tar them (with spaces)
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If you have multiple files or directories and you want to zip them into independent *.gz file you can do this. Optional -type f -atime
find -name "httpd-log*.txt" -type f -mtime +1 -exec tar -vzcf {}.gz {} \;
This will compress
httpd-log01.txt
httpd-log02.txt
to
httpd-log01...