...se addresses are larger than the older IPv4 addresses. (Note that IPv6 usually uses 39 characters at most but there is also a special IPv6 notation for IPv4 addresses which in its full form can be up to 45 characters. So if you know what you are doing you can use 39 characters, but if you just want...

... so are numerous, to list some of them: Support for descriptors. Specifically, the following constructs are made possible with descriptors: classmethod: A method that receives the class as an implicit argument instead of the instance. staticmethod: A method that does not receive the implicit ar...

...ent } return n; } }); 1 Alternatively, if you'd like to target all arrays, you could override Array.prototype.push(). Use caution, though; other code in your environment may not like or expect that kind of modification. Still, if a catch-all sounds appealing, just replace myArray with Ar...

...le<T> sequence. For just IEnumerable<T>, then Any() will generally be quicker, as it only has to look at one iteration. However, note that the LINQ-to-Objects implementation of Count() does check for ICollection<T> (using .Count as an optimisation) - so if your underlying data-sou...

... A restrict-qualified pointer (or reference)... ! ...is basically a promise to the compiler that for the scope of the pointer, the target of the pointer will only be accessed through that pointer (and pointers copied from it). In C++ compilers that support it i...

...a notation "Θ" (which is a two-side bound). In my experience, this is actually typical of discussions in non-academic settings. Apologies for any confusion caused. Big O complexity can be visualized with this graph: The simplest definition I can give for Big-O notation is this: Big-O notation is ...

... & part two being the confusion surrounding Training set. In general all of Machine Learning Algorithms need to be trained for supervised learning tasks like classification, prediction etc. or for unsupervised learning tasks like clustering. During the training step, the algorithms are taught...

...n GCC and Clang. Consider the following Makefile CPPFLAGS:=-std=c11 -W -Wall -pedantic -Werror .PHONY: all all: puts for building the following puts.c source code #include <stdio.h> int main(int argc, const char *argv[]) { while (*++argv) puts(*argv); return 0; } It will not c...

... This code will work, but isn't that pretty. It first divides all three values (it floors the values, so you 'lose' the remainder), and then divides the remainder: long n = x / 3 + y / 3 + z / 3 + ( x % 3 + y % 3 + z % 3 )...

Following links explain x86-32 system call conventions for both UNIX (BSD flavor) & Linux: 4 Answers ...