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SQLite with encryption/password protection
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113
SQLite has hooks built-in for encryption which are not used in the normal distribution, but he...
Fastest sort of fixed length 6 int array
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edited Aug 24 '11 at 11:35
Martijn
6,34733 gold badges2626 silver badges3636 bronze badges
an...
Try-catch speeding up my code?
...g issue).
Disassembled code for fast version:
[0000] push ebp
[0001] mov ebp,esp
[0003] push edi
[0004] push esi
[0005] push ebx
[0006] sub esp,1Ch
[0009] xor eax,eax
[000b] mov dword ptr [ebp-20h],eax
[000e] mov dword pt...
Animation CSS3: display + opacity
...n use fractions of a percent, it's better practice to use something like 0.001% rather that 1% because it minimizes the delay to "start", which can become apparent with longer animation durations
– Zach Saucier
Jul 4 '16 at 15:58
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App Inventor 2 低功耗蓝牙(BLE) 硬件接入、数据通信及IO控制 - App Invent...
...数 + 16位UUID的形式，由厂商定义，如BLE串口服务的UUID是0x001，使用的UUID基数是：6E400001-B5A3-F393-E0A9-E50E24DCCA9E。标准16位UUID技术文档请参考：https://www.bluetooth.com/specifications/assigned-numbers/。
点此自助购买 以上演示的aia源码。BLE...
Why do I get TypeError: can't multiply sequence by non-int of type 'float'?
...ta=1-alpha
C = (-math.log(1-beta))/alpha
coff = [0.0,0.01,0.0,0.35,0.98,0.001,0.0]
coff *= C
The error:
coff *= C
TypeError: can't multiply sequence by non-int of type 'float'
The solution - convert the list to numpy array:
coff = np.asarray(coff) * C
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How do I get an empty array of any size in python?
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Sven MarnachSven Marnach
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How to see the changes between two commits without commits in-between?
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answered Jul 28 '09 at 1:11
OneOfOneOneOfOne
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RSA Public Key format
...cons: SEQUENCE
4:d=1 hl=4 l= 257 prim: INTEGER :FB1199FF0733F6E805A4FD3B36CA68E94D7B974621162169C71538A539372E27F3F51DF3B08B2E111C2D6BBF9F5887F13A8DB4F1EB6DFE386C92256875212DDD00468785C18A9C96A292B067DDC71DA0D564000B8BFD80FB14C1B56744A3B5C652E8CA0EF0B6FDA64ABA47E3A4E89423C02...