大约有 43,000 项符合查询结果（耗时：0.0200秒） [XML]
TaifunPlayer 扩展（Audio Player）：音频播放器扩展，支持流媒体播放控制 ...
...放
播放控制：播放、暂停、停止、前进、后退、前进到位置
播放状态：检查播放状态（是否正在播放）
循环模式：设置播放循环模式
静音控制：设置播放器静音状态
时长获取：获取媒体文件的总时长和当前位置
播放...
滚动布局管理器拓展 - ScrollArrangementHandler · App Inventor 2 中文网
...触发此事件
布局滚动到最左端()
当布局滚动到最左端位置时触发此事件
布局滚动到最右端()
当布局滚动到最右端位置时触发此事件
布局发生滚动(滚动位置X 数值)
当布局位置发生改变时触发此事件，参数为当前水平滚...
Get user info via Google API
...tion is done, get the information from - https://www.googleapis.com/oauth2/v1/userinfo?alt=json
It has loads of stuff - including name, public profile url, gender, photo etc.
share
|
improve this...
How do I get currency exchange rates via an API such as Google Finance? [closed]
...0%22USDCHF%22%29
Open Source Exchange Rates API
Free for personal use (1000 hits per month)
Changing "base" (from "USD") is not allowed in Free account
Requires registration.
Request: http://openexchangerates.org/latest.json
Response:
<!-- language: lang-js -->
{
"disclaimer"...
Convert a row of a data frame to vector
...eful if your row contains a factor. Here is an example:
df_1 = data.frame(V1 = factor(11:15),
V2 = 21:25)
df_1[1,] %>% as.numeric() # you expect 11 21 but it returns
[1] 1 21
Here is another example (by default data.frame() converts characters to factors)
df_2 = data.frame...
Choice between vector::resize() and vector::reserve()
... the only effect.
So it depends on what you want. If you want an array of 1000 default items, use resize(). If you want an array to which you expect to insert 1000 items and want to avoid a couple of allocations, use reserve().
EDIT: Blastfurnace's comment made me read the question again and reali...
How can I determine whether a 2D Point is within a Polygon?
...ine NO 0
#define YES 1
#define COLLINEAR 2
int areIntersecting(
float v1x1, float v1y1, float v1x2, float v1y2,
float v2x1, float v2y1, float v2x2, float v2y2
) {
float d1, d2;
float a1, a2, b1, b2, c1, c2;
// Convert vector 1 to a line (line 1) of infinite length.
// We wa...
How to check if all of the following items are in a list?
...
What if your lists contain duplicates like this:
v1 = ['s', 'h', 'e', 'e', 'p']
v2 = ['s', 's', 'h']
Sets do not contain duplicates. So, the following line returns True.
set(v2).issubset(v1)
To count for duplicates, you can use the code:
v1 = sorted(v1)
v2 = sorted(v2...
Google Maps: how to get country, state/province/region, city given a lat/long value?
...ata.results[0];
var county, city;
$.each(loc1, function(k1,v1) {
if (k1 == "address_components") {
for (var i = 0; i < v1.length; i++) {
for (k2 in v1[i]) {
if (k2 == "types") {
var types = v...
Version number comparison in Python
...to pad the sequences.
from itertools import izip_longest
def version_cmp(v1, v2):
parts1, parts2 = [map(int, v.split('.')) for v in [v1, v2]]
parts1, parts2 = zip(*izip_longest(parts1, parts2, fillvalue=0))
return cmp(parts1, parts2)
With lower versions, some map hackery is required....