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Linux反编译全攻略 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术
...sh ebp
08048971 89 E5 mov ebp, esp
08048973 81 EC 08 00 00 00 sub esp, 0x8
08048979 68 00 00 00 00 push 0x0
0804897E 68 03 00 00 00 push 0x3
08048983 E8 88 FE FF FF ...
Code Golf: Collatz Conjecture
...;
section .text
global main
extern printf
extern atoi
main:
cmp dword [esp+0x04], 2
jne .usage
mov ebx, [esp+0x08]
push dword [ebx+0x04]
call atoi
add esp, 4
cmp eax, 0
je .usage
mov ebx, eax
push eax
push msg
.loop:
mov [esp+0x04], ebx
call printf
test ebx, 0x01
...
蓝牙通信接收的信息出现乱码？ - App应用开发 - 清泛IT社区，为创新赋能！
ESP32发送的是英文字符和数字,编译的蓝牙APP接收的是乱码
请问怎么解决以上问题?我们已经解决过类似问题，有一篇深入的乱码的原理及解决思路的文章：https://www.fun123.cn/reference/iot/bluetooth_codec.html
这里仅提供一下思路：
1、...
Is “for(;;)” faster than “while (TRUE)”? If not, why do people use it?
... while(42) is the coolest, produces no different result with respect to while(1) or while(true) or while(!0), and has philosophical meaning. I suppose for(;;) is parsed faster than the others anyway
– ShinTakezou
Jun 10 '10 at 12:21
...
BSS段、数据段、代码段、堆与栈 剖析 - C/C++ - 清泛网 - 专注C/C++及内核技术
...i$ = -404
_main PROC NEAR
; File test.cpp
; Line 13
push ebp
mov ebp, esp
sub esp, 404 ; 00000194H
push edi
; Line 14
mov DWORD PTR _run$[ebp], 1
mov DWORD PTR _run$[ebp+4], 2
mov DWORD PTR _run$[ebp+8], 3
mov DWORD PTR _run$[ebp+12], 4
mov DWORD PTR _run$[ebp+16], 5
mov DWORD PTR _run...
C++对象布局及多态探索之菱形结构虚继承 - C/C++ - 清泛网 - 专注C/C++及内核技术
...到子类的成员变量。
01 00426C00 push ebp
02 00426C01 mov ebp,esp
03 00426C03 sub esp,0CCh
04 00426C09 push ebx
05 00426C0A push esi
06 00426C0B push edi
07 00426C0C push ecx
08 00426C0D lea edi,[ebp+FFFFFF34h]
09 00426C13 mov ecx,33h
10 00426C18 mov eax,0CCCCCCCCh
11 ...
When should the volatile keyword be used in C#?
...es before and after reads and
writes may be observed to be ordered with respect to each other.
Certain operations such as creating a new thread, entering a lock, or
using one of the Interlocked family of methods introduce stronger
guarantees about observation of ordering. If you want more de...
How exactly does the callstack work?
...standing of how the low level operations of programming languages work and especially how they interact with the OS/CPU. I've probably read every answer in every stack/heap related thread here on Stack Overflow, and they are all brilliant. But there is still one thing that I didn't fully understand...
Is there any overhead to declaring a variable within a loop? (C++)
...0) { var = 4; } }
gcc -S 1.c
1.s:
_main:
pushl %ebp
movl %esp, %ebp
subl $24, %esp
movl $0, -16(%ebp)
jmp L2
L3:
movl $4, -12(%ebp)
L2:
cmpl $99, -16(%ebp)
jle L3
leave
ret
2.c
main() { while(int i < 100) { int var = 4; } }
gcc -S ...
What is the purpose of the EBP frame pointer register?
...ocal variable or an argument is at with a single constant offset. Although ESP's value changes over the course of execution, EBP remains the same making it possible to reach the same variable at the same offset (such as first parameter will always be at EBP+8 while ESP offsets can change significant...