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汇编常用寄存器及指令基础总结 - C/C++ - 清泛网 - 专注C/C++及内核技术
汇编常用寄存器及指令基础总结8086汇编常用寄存器数据寄存器AH&AL=AX：累加寄存器，常用于运算BH&BL=BX：基址寄存器，常用于地址索引CH&CL=CX：计数寄存器，常用于计数DH...8086汇编常用寄存器
数据寄存器
AH&AL=AX：累加寄存器，...
MFC CString::Format()函数详解 - C/C++ - 清泛网 - 专注C/C++及内核技术
...
lf输入输出double型数据
m数据输出宽度为m
.n输出小数位数为n
2、Args是一个变体数组，即它里面可以有多个参数，而且每个参数可以不同。
如以下例子：
Format("my name is %6s","wind");
返回后就是
my name is wind
现在来看...
Purpose of memory alignment
...g study of the tradeoffs between speed and cost, it was basically a 16-bit 8086 (which had a full 16-bit external bus) but with only half the bus-lines to save production costs. Because of this the 8088 needed twice the clock cycles to access memory than the 8086 since it had to do two reads to get ...
App Inventor 2 列表的函数式编程 · App Inventor 2 中文网
...得到每日利润列表（映射），然后
将每日所有利润条目相加，得到总利润（缩减）。
第1步：过滤
Berry 需要返回一个新列表，该列表是通过过滤原始列表而产生的，以便消除“N/A”条目，并且列表中仅存在数字。
过滤器...
Why is x86 ugly? Why is it considered inferior when compared to others? [closed]
...ssible reasons for it:
x86 is a relatively old ISA (its progenitors were 8086s, after all)
x86 has evolved significantly several times, but hardware is required to maintain backwards compatibility with old binaries. For example, modern x86 hardware still contains support for running 16 bit code na...
Why do x86-64 systems have only a 48 bit virtual address space?
...
@bdares: Bad analogy. The 8088/8086 arch's instruction set has a 640k limit built into it. Only making a new ISA (386) was it possible to break the barrier. x86_64 on the other hand supports all 64 bits in the ISA. It's just the current-generation hardware...
What is the “FS”/“GS” register intended for?
...if one is willing to round memory allocations up to multiples of 16 bytes, 8086-style segmentation allows one to use the segment alone as a means of identifying an object. Rounding allocations up to 16 bytes might have been slightly irksome in 1980, but would represent a win today if it reduced the...
cpuid汇编指令 - C/C++ - 清泛网 - 专注C/C++及内核技术
...小在EAX的bit[15:8]返回，返回的内容为虚拟（物理）地址的位数。例如在我的机器上的运行结果如下：
表明我的机器支持36位的物理地址和48位的虚拟地址。
摘自： 原文链接 链接2
在C++中使用：
unsigned int processor=0;//首...
Simulator or Emulator? What is the difference?
... result/outcome is always the same as the original object. For example, EMU8086 emulates the 8086 microprocessor on your computer, which obviously is not running on 8086 (= different protocols), but the output it gives is what a real 8086 would give.
...
64 bit OS下int占几个字节？ - C/C++ - 清泛网 - 专注C/C++及内核技术
...论32/64位编译器、32/64位OS，结果都是4。
只与编译器位数有关，与OS位数无关，但64位程序不能运行在32位OS上。64bit int 字节