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周鸿祎创业以来的“六大战役” 酷派会是最后一战 - 资讯 - 清泛网 - 专注C/...
...，中国雅虎正式放弃发展3721和雅虎助手的业务，3721“网络实名”软件正式淡出互联网舞台。
至此这场纠纷以周鸿祎全面胜出而结束，其中的是是非非，从事件的前因后果来看， 周鸿祎只不过是继续完成在雅虎未完成的梦想，...
App Inventor 2 UrsAI2UDP 拓展 - UDP广播通信协议 · App Inventor 2 中文网
...只需将广播数据报发送到先前约定的端口，发送到本地网络上的所有设备，请求它们的连接数据。在约定端口上监听的设备随后将其 IP 和可能的其他数据返回给发送者。发送者收集答案，从而知道所有活动设备。由于 UDP 数据包...
廉价共享存储解决方案1-drbd+ha+nfs - 更多技术 - 清泛网 - 专注C/C++及内核技术
...，使用Rsync对文件夹进行同步，会占用大量的磁盘I/O和网络带宽。同时如果正在拷贝的文件在大量频繁的更改，Rsync将会变得无所适从而产生冲突。
另一种情况假如 tomact2,tomcat3同步tomcat1的目录，当tomcat1挂了之后，负载均衡会...
NumPy array initialization (fill with identical values)
...
7 Answers
7
Active
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TLSF源码及算法介绍 - 开源 & Github - 清泛网 - 专注C/C++及内核技术
...mael Ripoll for his suggestions and reviews
*
* Copyright (C) 2008, 2007, 2006, 2005, 2004
*
* This code is released using a dual license strategy: GPL/LGPL
* You can choose the licence that better fits your requirements.
*
* Released under the terms of the GNU General Public License V...
Get the week start date and week end date from week number
...(dd, -(DATEPART(dw, WeddingDate)-1), WeddingDate) [WeekStart]
DATEADD(dd, 7-(DATEPART(dw, WeddingDate)), WeddingDate) [WeekEnd]
You probably also want to look at stripping off the time from the date as well though.
share
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Expand a random range from 1–5 to 1–7
...1 to 5, write a function which produces a random integer in the range 1 to 7.
78 Answers
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Datetime - Get next tuesday
... if it's already Tuesday":
DateTime today = DateTime.Today;
// The (... + 7) % 7 ensures we end up with a value in the range [0, 6]
int daysUntilTuesday = ((int) DayOfWeek.Tuesday - (int) today.DayOfWeek + 7) % 7;
DateTime nextTuesday = today.AddDays(daysUntilTuesday);
If you want to give "a week...
Regular expression that matches valid IPv6 addresses
...of rfc5952)
link-local IPv6 addresses with zone index (section 11 of rfc4007)
IPv4-Embedded IPv6 Address (section 2 of rfc6052)
IPv4-mapped IPv6 addresses (section 2.1 of rfc2765)
IPv4-translated addresses (section 2.1 of rfc2765)
IPv6 Regular Expression:
(([0-9a-fA-F]{1,4}:){7,7}[0-9a-fA-F]{1,4...
Split a vector into chunks in R
...nk all you need is seq_along(), split() and ceiling():
> d <- rpois(73,5)
> d
[1] 3 1 11 4 1 2 3 2 4 10 10 2 7 4 6 6 2 1 1 2 3 8 3 10 7 4
[27] 3 4 4 1 1 7 2 4 6 0 5 7 4 6 8 4 7 12 4 6 8 4 2 7 6 5
[53] 4 5 4 5 5 8 7 7 7 6 2 4 3 3...