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Fastest way to check a string contain another substring in JavaScript?

...string (I just need the boolean value)? Could you please suggest your idea and sample snippet code? 8 Answers ...
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LINQ equivalent of foreach for IEnumerable

...use ToList() creates a copy of the sequence, which could cause performance and memory issues. – decasteljau Aug 14 '09 at 12:37 17 ...
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Sorting multiple keys with Unix sort

...s that need to be sorted by 1-n keys. Some of these keys might be numeric and some of them might not be. This is a fixed-width columnar file so there are no delimiters. ...
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The import android.support cannot be resolved

...g to run the code provided HERE I downloaded the code from their Github and imported into Android SDK, but it shows error at the lines ...
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String.equals versus == [duplicate]

This code separates a string into tokens and stores them in an array of strings, and then compares a variable with the first home ... why isn't it working? ...
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In MySQL what does “Overhead” mean, what is bad about it, and how to fix it?

...x paths, defragmenting, etc. is what is known as OPTIMIZATION in mysql and other terms in other databases. For example, IBM DB2/400 calls it REORGANIZE PHYSICAL FILE MEMBER. It's kind of like changing the oil in your car or getting a tune-up. You may think you really don't have to, ...
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Difference between .keystore file and .jks file

I have tried to find the difference between .keystore files and .jks files, yet I could not find it. I know jks is for "Java keystore" and both are a way to store key/value pairs. ...
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Are delphi variables initialized with a value by default?

I'm new to Delphi, and I've been running some tests to see what object variables and stack variables are initialized to by default: ...
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No route matches “/users/sign_out” devise rails 3

I've installed devise on my app and applied the following in my application.html.erb file: 29 Answers ...
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Generate all permutations of a list without adjacent equal elements

... return output Proof of correctness For two item types, with counts k1 and k2, the optimal solution has k2 - k1 - 1 defects if k1 < k2, 0 defects if k1 = k2, and k1 - k2 - 1 defects if k1 > k2. The = case is obvious. The others are symmetric; each instance of the minority element prevents ...