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Javascript Object push() function
... not objects, so use the right data structure.
var data = [];
// ...
data[0] = { "ID": "1", "Status": "Valid" };
data[1] = { "ID": "2", "Status": "Invalid" };
// ...
var tempData = [];
for ( var index=0; index<data.length; index++ ) {
if ( data[index].Status == "Valid" ) {
tempData.p...
Unable to find valid certification path to requested target - error even after cert imported
...
10 Answers
10
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How to find the width of a div using vanilla JavaScript?
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edited Jul 11 '16 at 8:06
answered Jan 24 '11 at 21:48
A...
Selector on background color of TextView
...ctor. So, the necessary changes would look like this:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:state_pressed="true"
android:drawable="@drawable/selected_state" />
</selector>...
How much is the overhead of smart pointers compared to normal pointers in C++?
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answered Mar 10 '14 at 9:17
lisyaruslisyarus
12.9k33 gold badges3737 silver badges5858 bronze badges
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Set selected index of an Android RadioGroup
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202
If your radio group is defined in a layout xml file, each button can be assigned an id. Then y...
Error in finding last used cell in Excel with VBA
...h any of the methods given below, it will give you 5. Now color the cell A10 red. If you now use the any of the below code, you will still get 5. If you use Usedrange.Rows.Count what do you get? It won't be 5.
Here is a scenario to show how UsedRange works.
xlDown is equally unreliable.
Consid...
getExtractedText on inactive InputConnection warning on android
...1214): getTextAfterCursor on inactive InputConnection
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I/Choreographer(20010): Skipped 30 frames! The application may be doing too much work on its main thread.
My situation:
I have an EditText view the user types into. The EditText gets cleared when user presses a button. Lots of inactive Inp...
How to make a transparent UIWebView
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303
I recommend:
webView.opaque = NO;
webView.backgroundColor = [UIColor clearColor];
(setting t...
Android Split string
...they taste good";
String[] separated = currentString.split(":");
separated[0]; // this will contain "Fruit"
separated[1]; // this will contain " they taste good"
You may want to remove the space to the second String:
separated[1] = separated[1].trim();
If you want to split the string with a spe...