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Pandas: create two new columns in a dataframe with values calculated from a pre-existing column

... from pandas import * In [2]: def calculate(x): ...: return x*2, x*3 ...: In [3]: df = DataFrame({'a': [1,2,3], 'b': [2,3,4]}) In [4]: df Out[4]: a b 0 1 2 1 2 3 2 3 4 In [5]: df["A1"], df["A2"] = zip(*df["a"].map(calculate)) In [6]: df Out[6]: a b A1 A2 0 1 2 2...
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Implement Stack using Two Queues

... 23 Answers 23 Active ...
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Python - Create list with numbers between 2 values?

...t returns a list so all you need is: >>> range(11, 17) [11, 12, 13, 14, 15, 16] In Python 3.x range is a iterator. So, you need to convert it to a list: >>> list(range(11, 17)) [11, 12, 13, 14, 15, 16] Note: The second number is exclusive. So, here it needs to be 16+1 = 17 E...
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Why are Python lambdas useful? [closed]

...where you can pass functions to other functions to do stuff. Example: mult3 = filter(lambda x: x % 3 == 0, [1, 2, 3, 4, 5, 6, 7, 8, 9]) sets mult3 to [3, 6, 9], those elements of the original list that are multiples of 3. This is shorter (and, one could argue, clearer) than def filterfunc(x): ...
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How to convert a scala.List to a java.util.List?

...ort scala.collection.jcl.ArrayList unconvertList(new ArrayList ++ List(1,2,3)) From Scala 2.8 onwards: import scala.collection.JavaConversions._ import scala.collection.mutable.ListBuffer asList(ListBuffer(List(1,2,3): _*)) val x: java.util.List[Int] = ListBuffer(List(1,2,3): _*) However, asLis...
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Pickle incompatibility of numpy arrays between Python 2 and 3

I am trying to load the MNIST dataset linked here in Python 3.2 using this program: 7 Answers ...
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How to swap keys and values in a hash

... (in essence, by letting you access keys through values): {a: 1, b: 2, c: 3}.key(1) => :a If you want to keep the inverted hash, then Hash#invert should work for most situations: {a: 1, b: 2, c: 3}.invert => {1=>:a, 2=>:b, 3=>:c} BUT... If you have duplicate values, invert will...
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Removing duplicates in lists

...ample should cover whatever you are trying to do: >>> t = [1, 2, 3, 1, 2, 5, 6, 7, 8] >>> t [1, 2, 3, 1, 2, 5, 6, 7, 8] >>> list(set(t)) [1, 2, 3, 5, 6, 7, 8] >>> s = [1, 2, 3] >>> list(set(t) - set(s)) [8, 5, 6, 7] As you can see from the example resu...
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No secret option provided to Rack::Session::Cookie warning?

I am running Rails 3.2.3, Ruby 1.9 under Fedora 17. I get this warning, when I run rails s , and how do I fix? 7 Answers ...
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[] and {} vs list() and dict(), which is better?

...gt;> from timeit import timeit >>> timeit("[]") 0.040084982867934334 >>> timeit("list()") 0.17704233359267718 >>> timeit("{}") 0.033620194745424214 >>> timeit("dict()") 0.1821558326547077 and for non-empty: >>> timeit("[1,2,3]") 0.24316302770330367 ...